When an object is free-falling, no other force is acting upon it but the gravitational force. Because of this, the equations of motion are simplified. We can determine first the initial velocity:
v = √2gy = √2(9.81)(4.9) = 9.805 m/s
Then, we use this to the equation below:
y = vt + 1/2*at²
y = (9.805)(0.5) + 1/2(9.81)(0.5)²
y = 6.13 m
<span>0.166666666667
Hope this helped!
STSN</span>
Answer:
4s
Explanation:
My assumption would be 4s since 25 going into 100 would be 4? hope that helped..
Answer:
curves downward, below the initial velocity vector.
Explanation:
Projectile launches are generally divided into two types: the oblique throw and the free fall. The free fall of bodies consists of throwing or abandoning projectiles from a hill or any unevenness that has a height in relation to a frame (usually the ground), while the oblique launch consists of launching a projectile at an angle. any relative to a frame (usually the ground).
Regardless of the type, when reading the paragraph above, we can say that the trajectory of a projectile will always be curved down and below the initial velocity vector.