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IRINA_888 [86]
3 years ago
10

What did early experiments and Coulomb’s Law describe? Select all that apply. The further away two charged objects are the stron

ger the electrical force between them. Like charges attract and opposite charges repel. The closer two charged objects are the weaker the electrical force between them. The closer two charged objects are the stronger the electrical force between them. Like charges repel and opposite charges attract. The further away two charged objects are the weaker the electrical force between them.
Physics
1 answer:
LenKa [72]3 years ago
5 0

Answer:

The closer two charged objects are the stronger the electrical force between them.

Like charges repel and opposite charges attract.

The further away two charged objects are the weaker the electrical force between them.

Explanation:

Coulomb's law tells  us about the electric force/electrostatic force/Coulomb force between two charged particles. The force (F) between the particles Q and q, separated by a distance r is given as,

F = k\frac{Qq}{r^{2}}

where k = Coulomb constant.

It is evident from the equation that closer the charged particle force will be more. As the distance between the charge increases the force will be weaker. Also the like charges will repel and opposite charges will attract.

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Answer:

option E

Explanation:

the correct answer is option E

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Put you palm in the direction of electric field and curl your finger in the direction of magnetic field which east direction.

 now, the direction shown by the thumb will be the direction of magnetic field  which comes out to be toward South direction.

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What property of equality can be used to solve the equation. n – 14 = 25
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2 years ago
A race is held between a sports car and a motorcycle. The sports car can accelerate at 5.0 m/s^2 and the motorcycle can accelera
user100 [1]

Answer:

Vf₁ = 30 m/s

s₂ = 90 m

car wins the race.

Explanation:

To find the speed of car after 5 s, we use 1st equation of motion:

Vf₁ = Vi₁ + a₁t₁

where,

Vf₁ = Final Speed of Car = ?

Vi₁ = Initial Speed of Car = 0 m/s

a₁ = acceleration of car = 5 m/s²

t₁ = time = 5 s

Therefore,

Vf₁ = 0 m/s + (5 m/s²)(5 s)

<u>Vf₁ = 25 m/s</u>

<u></u>

To find the distance of motorcycle after 6 s, we use 2nd equation of motion:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₂ = distance covered by the motorcycle = ?

Vi₁ = Initial Speed of motorcycle = 0 m/s

a₂ = acceleration of motorcycle = 8 m/s²

t₂ = time = 6 s

Therefore,

s₂ = (0 m/s)(6 s) + (1/2)(5 m/s²)(6 s)²

<u>s₂ = 90 m</u>

<u></u>

We can use 2nd equation of motion to find time taken by each car and motorcycle to reach the finish point:

For Car:

s₁ = Vi₁ t₁ + (1/2)a₁t₁²

where,

s₁ = 200 m - 50 m = 150 m (since, car starts 50 m ahead)

Therefore.

150 m = (0 m/s)(t₁) + (1/2)(5 m/s²)t₁²

t₁ = √60 s²

t₁ = 7.74 s

For Motorcycle:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₁ = 200 m

Therefore.

200 m = (0 m/s)(t₂) + (1/2)(5 m/s²)t₂²

t₂ = √80 s²

t₂ = 8.94 s

Since, the car takes less time to reach finish line.

Therefore, car wins the race.

5 0
3 years ago
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