The planet Mercury. Hope this helps
<h2>0.054×2.33×90</h2><h3>=0.11582×90</h3><h3>=11.3238</h3>
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Force applied on the car due to engine is given as
towards right
Also there is a force on the car towards left due to air drag
towards left
now the net force on the car will be given as

now we can say that since the two forces are here opposite in direction so here the vector sum of two forces will be the algebraic difference of the two forces.
So we can say



So here net force on the car will be 150 N towards right and hence it will accelerate due to same force.
2.7549 x 10^4 is the answer I hope this helped u
Here, height is given which will be the distance for a freely falling object.
The velocity will be

and the acceleration will be

In this way, the formula works.