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IRINA_888 [86]
3 years ago
10

What did early experiments and Coulomb’s Law describe? Select all that apply. The further away two charged objects are the stron

ger the electrical force between them. Like charges attract and opposite charges repel. The closer two charged objects are the weaker the electrical force between them. The closer two charged objects are the stronger the electrical force between them. Like charges repel and opposite charges attract. The further away two charged objects are the weaker the electrical force between them.
Physics
1 answer:
LenKa [72]3 years ago
5 0

Answer:

The closer two charged objects are the stronger the electrical force between them.

Like charges repel and opposite charges attract.

The further away two charged objects are the weaker the electrical force between them.

Explanation:

Coulomb's law tells  us about the electric force/electrostatic force/Coulomb force between two charged particles. The force (F) between the particles Q and q, separated by a distance r is given as,

F = k\frac{Qq}{r^{2}}

where k = Coulomb constant.

It is evident from the equation that closer the charged particle force will be more. As the distance between the charge increases the force will be weaker. Also the like charges will repel and opposite charges will attract.

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3 years ago
The weight of an object is the same on two different planets. The mass of planet A is only sixty percent that of planet B. Find
natka813 [3]

Answer:

0.775

Explanation:

The weight of an object on a planet is equal to the gravitational force exerted by the planet on the object:

F=G\frac{Mm}{R^2}

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the object

R is the radius of the planet

For planet A, the weight of the object is

F_A=G\frac{M_Am}{R_A^2}

For planet B,

F_B=G\frac{M_Bm}{R_B^2}

We also know that the weight of the object on the two planets is the same, so

F_A = F_B

So we can write

G\frac{M_Am}{R_A^2} = G\frac{M_Bm}{R_B^2}

We also know that the mass of planet A is only sixty percent that of planet B, so

M_A = 0.60 M_B

Substituting,

G\frac{0.60 M_Bm}{R_A^2} = G\frac{M_Bm}{R_B^2}

Now we can elimanate G, MB and m from the equation, and we get

\frac{0.60}{R_A^2}=\frac{1}{R_B^2}

So the ratio between the radii of the two planets is

\frac{R_A}{R_B}=\sqrt{0.60}=0.775

6 0
3 years ago
PLEASEEEEEE HELPPPPPPP<br><br> Define resistance and discuss how it affects current.
PIT_PIT [208]

Answer:

Resistance is the opposing of the flow of current through a conductor.

7 0
3 years ago
two truckers are traveling directly away from each other at the same speed. If one trucker sounds her horn at a frequency of 206
boyakko [2]

Answer:

v' = 14.76 m/s

Explanation:

given,

frequency of the one truck = 206 Hz

apparent frequency ,f' = 189 Hz

speed of sound, v = 343 m/s

speed of observer (v_o)and source (v_s) = v'

now, using Doppler's effect

f' = \dfrac{v-v_o}{v+v_s}\ f

f' = \dfrac{v- v'}{v+v'}\ f

189 = \dfrac{343- v'}{343+v'}\ 206

0.9174= \dfrac{343- v'}{343+v'}

314.69 + 0.9174 v' = 343 - v'

1.9174 v' = 28.30

v' = 14.76 m/s

hence, the speed of the truck is equal to 14.76 m/s

3 0
4 years ago
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