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PtichkaEL [24]
3 years ago
10

The amount of power required to move an object can be increased without changing the

Physics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

Yes it is possible to increase the power with out changing the amount of work.

Explanation:

The power is defined by the amount of power divided by the time. This time is the one needed to do the work. We can understand this issue by analyzing an example with numeric values.

Work = 500 [J]

Time = 5 [s]

Power will be:

Power=\frac{500}{5} \\Power=100 []watt]\\

Now if we change the time to 2 seconds:

Power = 500 [J]/2[s]\\Power = 250 [watt]\\

As we can see, the power was increased without the need to change the work.

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If a pedestrian walked 900 meters forward and 300 meters back
serious [3.7K]

Answer:

B

Explanation:

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2 years ago
Which of the following electron configurations for neutral atoms is correct?
liq [111]
Nitrogen: 1s2, 2s2, 2p3 is correct answer.
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A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
Alex787 [66]

Answer:

a) 1.092 m/s

b) 0.33 m

c) 0.25 m

Explanation:

To start with, from the formula of wave, we know that

v = f λ, where

v = velocity of wave

f = frequency of the wave

λ = wavelength of the wave

Again, on another hand, we know that

T = 1/f, where T = period of the wave

From the question, we are given that

t = 2.7 s

d = 0.66 m

λ = 5.9 m

Period, T = 2 * t

Period, T = 2 * 2.7

Period, T = 5.4 s

If T = 1/f, then f = 1/T, thus

Frequency, f = 1/5.4

Frequency, f = 0.185 hz

Remember, v = f λ

v = 0.185 * 5.9

v = 1.092 m/s

Amplitude, A = d/2

Amplitude, A = 0.66/2

Amplitude, A = 0.33 m

If the other distance travelled by the boat is 0.5, then Amplitude is

A = 0.5/2

A = 0.25 m

6 0
3 years ago
The Pacific Giant Kelp grows at a rate of 18 in/day. How many centimeters per hour is this?
Airida [17]

For this case we must do a conversion. By definition we have to:

1 inch equals 2.54 centimeters

1 day equals 24 hours.

So, we have:18 \frac {in} {day} * \frac {1} {24} \frac {day} {h} * \frac {2.54} {1} \frac {cm} {in} =

Canceling units we have:

\frac {18 * 1 * 2.54} {24 * 1} \frac {cm} {h} =\\\frac {45.72} {24}\frac {cm} {h} =

1,905 \frac {cm} {h}

Answer:

1,905 \frac {cm} {h}

5 0
3 years ago
An airplane flies 1350km in 2 1/4 hours. What is its average speed in kilometers per hour?
Brut [27]
600km since it would be 1350 divided by 2.25
8 0
3 years ago
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