r₁ = distance of the point from the source = 43 km = 43000 m
I₁ = intensity of earthquake wave at distance "r₁" = 2.5 x 10⁶ W/m²
r₂ = distance of the point from the source = 1.5 km = 1500 m
I₂ = intensity of earthquake wave at distance "r₂" = ?
we know that , for a constant power , the intensity of wave is inversely proportional to the distance from the source .
I α 1/r² where I = intensity of wave , r = distance from source
hence we can write
I₁/I₂ = r₂²/r₁²
inserting the values
(2.5 x 10⁶) /I₂ = (1500/43000)²
I₂ = 2.1 x 10⁹ W/m²
Answer:
The magnitude of the net force is 5430N
Explanation:
I suggest to define the axes as aligned to the axis of the plane. This will require you to decompose only one vector, namely the Weight. We need two components of the W force: one in horizontal direction of the plane, the other perpendicular to it. Through a simple triangle argument you will se that the plane-horizontal component of W is

acting in the direction of the Drag, and the plane-perpendicular component is:

with negative sign since it counteracts the Lift.
So the components of the netforce F are:

The magnitude of the net force is:

Answer:
the resulting angular speed after she pulls her hand inwards in (rad/s) is 27.02 rad/s
Explanation:
Given that :
the initial angular speed 
Initial rotational inertia 
Final angular speed 
Final rotational inertia 
According to conservation of momentum :
Initial momentum = final momentum




To rad/s ; we have:



Therefore the resulting angular speed after she pulls her hand inwards in (rad/s) = 27.02 rad/s