Answer:
maximum speed of the bananas is 18.8183 m/s
Explanation:
Given data
amplitude A = 23.195 cm
spring constant K = 15.2676 N/m
mass of the bananas m = 56.9816 kg
to find out
maximum speed of the bananas
solution
we know that radial oscillation frequency formula that is = √(K/A)
radial oscillation frequency = √(15.2676/23.195)
radial oscillation frequency is 0.8113125 rad/s
so maximum speed of the bananas = radial oscillation frequency × amplitude
maximum speed of the bananas = 0.8113125 × 23.195
maximum speed of the bananas is 18.8183 m/s
A) Energy is absorbed in the reaction.
Such reactions are called endothermic reactions.
Get a direct answer of what???
The amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.
<h3>What is flow rate?:</h3>
This is the volume of fluid flowing in a vessel per unit time.
First, we need to get the volume of blood flowing through the venae cavae of the adult and the child in 1 hour, then subtract the volume of blood for the child from that of the adult.
Using,
- V = F'm................ Equation 1
Where:
- V = Volume of the blood
- F' = Flow rate
- m = mass of blood.
For the Adult,
Given:
Substitute these values into equation 1
For the child,
Given:
Substitute these values into equation 1 also
The amount of blood that flows more through the adult than the child is
- A = 5250-1500
- A = 3750 ml.
Hence, the amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.
Learn more about flow rate here: brainly.com/question/21630019