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Oksanka [162]
3 years ago
9

Average velocity is different than average speed because calculating average velocity involves

Physics
1 answer:
Artemon [7]3 years ago
8 0

Answer:

calculating displacement.

Explanation:

It's not true that displacement and distance would be the same always. Displacement is always smaller than or equal to distance as it is the smallest path between the initial and final point whereas distance is the measure of the total path covered.

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Salt is made in in the water the seaweeds have slat on them of you let the seaweeds dry you can see the salt on them.
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Two students pushes on a box in the same direction , and one pushes In The opposite direction.what is the net force on the box i
Rufina [12.5K]

If they are both pushing with the same force but in opposite directions,
and if there are no other forces on the box besides them pushing, then
the net force on the box is zero and it just lays there, as if there were
no forces on it at all.

4 0
4 years ago
A 20 kω resistor is connected in series with an initially uncharged 100 μf capacitor and a 5 v battery. What is the charge on th
madam [21]

Hi there!

We can use the equation for the charge of a charging capacitor:
q(t) = C\epsilon( 1 - e^{-\frac{t}{RC}})

Using Capacitor equations:
C = \frac{Q}{V}}\\\\Q = CV

Therefore, Cε equals the steady-state charge of the capacitor (the function approaches this value as t ⇒ ∞.


We can plug in the givens and solve.
\epsilon = 5 V\\\\C = 100\mu F = 0.0001 F

Q = C \epsilon = (0.0001)(5) = \boxed{0.0005 C}

4 0
2 years ago
Two objects attract each other gravitationally with a force of 2.5 x 10^-10N when they are 0.25 m apart. Their total mass is 4.0
In-s [12.5K]

Answer:

M = 3.9406 kg and m = 0.0594 kg

Explanation:

The gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically it is expressed as follows:

Fg = (G×M×m)/r²    Formula (1)

Where:

Fg is the gravitational force (N)

G is the universal gravitation constant, G = 6.67 × 10⁻¹¹ (N×m²)/kg²

M and m are the masses of the bodies that interact  (kg).

r is the distance that separates them (m).

Known Data

Fg = 2.5 × 10⁻¹⁰ N

r = 0.25 m

G = 6.67 × 10⁻¹¹ (N×m²)/kg²

Problem development

We propose 2 equations

M + m = 4kg

M = 4 - m equation (1)

We replace in formula (1)

2.5 × 10⁻¹⁰ = (6.67 × 10⁻¹¹ × M × m)/(0.25)²

2.5 × 10⁻¹⁰ × (0.25)² = (6.67 × 10⁻¹¹ × M × m)

(2.5 × 10⁻¹⁰ × (0.25)²)/(6.67 × 10⁻¹¹) = M × m

M × m = 0.234 equation (2)

We replace M = 4 - m in equation (2)

(4 - m) × m = 0.234

4m - m² = 0.234

m² - 4m + 0.234 = 0 (quadratic equation)

We apply the formula for the quadratic equation and obtain 2 values for m that meet the conditions:

m = 3.9406 kg or m =  0.0594 kg

We replace m in equation (1)

M = 4 - 3.9406 = 0.0594 kg or M = 4 - 0.0594 = 3.9406

To meet the condition that M + m must give 4 kg, one mass must be equal 3.9406 and the other must equal 0.0594, then:

M = 3.9406 kg and m = 0.0594 kg

6 0
4 years ago
What is the importance of discovering gravitational waves in science?
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<span>The importance of discovering gravitational waves are; one, we can measure the activity between two bodies in orbit in the universe, two, scientist can estimate the merging of two bodies in the universe every 15 minutes by using LIGO and three, we can know the behavior of other bodies that we did not know exist.</span>
4 0
3 years ago
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