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Lapatulllka [165]
3 years ago
9

A book with a mass of 2.2 kg rests on a table Find the force of the Earth on the book.

Physics
1 answer:
erik [133]3 years ago
3 0

Answer:

2.2 kg ×10=22 .. "10" is a gravitational field strength

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malfutka [58]

Answer:

45

Explanation:

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3 years ago
If you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out. This happens
amm1812

Answer:

True

Explanation:

If we swing a bucket of water fast enough in a vertical circle the water does not spill out even at the top-most position of the bucket. This happens because the centrifugal force acting away from the center in a circular motion neutralizes or overcomes the gravitational force on the water particles.

<u>Centrifugal force is mathematically related as:</u>

F=m.r.\omega^2

where:

m = mass of the revolving body

r = radius of revolution

\omega= angular velocity in radians per second

This force F acts in radially outward direction.

3 0
4 years ago
How much work<br> was done to<br> accelerate a 2.2<br> kg object from<br> rest to 26m/s?
Makovka662 [10]

Answer:

Explanation:

<em>work</em><em> </em><em>done</em><em> </em><em>=</em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>kinetic</em><em> </em><em>energy</em><em>,</em><em> </em><em>assuming</em><em> </em><em>there</em><em> </em><em>are</em><em> </em><em>no</em><em> </em><em>energy</em><em> </em><em>losses</em><em>.</em>

<em>work</em><em> </em><em>done</em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>m</em><em> </em><em>×</em><em> </em><em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>in</em><em> </em><em>v</em><em>^</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>2</em><em>.</em><em>2</em><em> </em><em>×</em><em> </em><em>(</em><em> </em><em>26</em><em>^</em><em>2</em><em> </em><em>-</em><em> </em><em>0</em><em>^</em><em>2</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>2</em><em>.</em><em>2</em><em> </em><em>×</em><em> </em><em>676</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>743</em><em>.</em><em>6</em><em> </em><em>joules</em>

4 0
2 years ago
What is 95°F on the Celsius scale?
svetlana [45]
95 degrees Fahrenheit in Celsius scale is 35 degrees Celsius
6 0
3 years ago
For light of wavelength 589 nm, calculate the critical angles for the following substances when surrounded by air.
NeX [460]

(1) The critical angles for the fused quartz is 44⁰,

(2) The critical angles for the polystyrene is 39⁰.

(3) The critical angles for the sodium chloride is 41⁰.

<h3>What is Critical angles?</h3>

In optics, the critical angle is the topmost angle at which a shaft of light traveling in one transparent medium can strike the boundary between that medium and another with a lower refractive indicator without being fully reflected within the first

Critical angles for the different medium.

θ=sin^{-1}\frac{n_{2} }{n_{1} }

where;

n_{2} is the refractive index of air = 1

n_{1} is the refractive index of the given substances.

Refractive index of quartz glass = 1.46

Refractive index of polystyrene = 1.59

Refractive index of sodium chloride = 1.54

Critical angles for quartz glass:

$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.46}\\$

$\theta_{\text {crit }}=44^{o}$

Critical angles for polystyrene

$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.59}\\\\

\theta_{\text {crit }}=39^{\circ}

Critical angles for Sodium Chloride

$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.54}\\

\theta_{\text {crit }}=41^{o}

Thus, the critical angles for the quartz glass is 44⁰, the critical angles for the polystyrene is 39 ⁰ and the critical angles for the sodium chloride is 41⁰.

To know more about critical angle visit:
brainly.com/question/3314727

#SPJ4

I understand that the question you are looking for is:

"For light of wavelength 589 nm, calculate the critical angles for the following substances when surrounded by air.

(a) Fused Quartz

(b) Polystyrene

(c) Sodium chloride"

8 0
2 years ago
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