Derive the kinetic equations for Vmax and KM using the transit time and net rate constant method as discussed in class and follo
wing the attached handout. (Hint: solve for ET/v by summing the inverse net rate constants, then invert to obtain v/ET and put it in the form of kcatS/[KM S]). Remember that if a step is irreversible, the net rate constant for that step is just the rate constant for that step.
1 answer:
Answer:
Rate = vmax k3/k2+k3
Explanation:
The rate of reaction when the enzyme is saturated with substrate is the maximum rate of reaction, is referred to as Vmax.
This is usually expressed as the Km ie. Michaelis constant of the enzyme, an inverse measure of affinity. For practical purposes, Km is the concentration of substrate which permits the enzyme to achieve half Vmax.
Please kindly check attachment for the step by step solution of the given problem.
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Answer:
Explanation:
a. Given that:
mass of first & second piece,
mass of 3rd piece,
-velocity of first piece(
) and
as velocity of 2nd piece (
)
Let be velocity of 3rd piece=?
#Vessel is at rest before explosion. Considering conservation of linear momentum:
#Dividing both sides by
#Plug the values:
#So the magnitude of the third piece is:
Magnitude of the 3rd piece is 10.84 m/s
b. To find direction of the magnitude (as an angle relative to the -axis), we find
. The angle is obtained by getting the tan inverse as:
-The direction of the magnitude (angle relative to the x-axis) is 45°