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hichkok12 [17]
3 years ago
7

Derive the kinetic equations for Vmax and KM using the transit time and net rate constant method as discussed in class and follo

wing the attached handout. (Hint: solve for ET/v by summing the inverse net rate constants, then invert to obtain v/ET and put it in the form of kcatS/[KM S]). Remember that if a step is irreversible, the net rate constant for that step is just the rate constant for that step.

Physics
1 answer:
Pepsi [2]3 years ago
6 0

Answer:

Rate = vmax k3/k2+k3

Explanation:

The rate of reaction when the enzyme is saturated with substrate is the maximum rate of reaction, is referred to as Vmax.

This is usually expressed as the Km ie. Michaelis constant of the enzyme, an inverse measure of affinity. For practical purposes, Km is the concentration of substrate which permits the enzyme to achieve half Vmax.

Please kindly check attachment for the step by step solution of the given problem.

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The asker of the second question needs a tutorial in radiometric dating. There is little likelihood that the daughter isotope has the same atomic weight as the parent isotope. To measure the mass isotopes doesn't tell us how many atoms of each exist. To get around that let's pretend — which will likely serve the purpose ineptly intended — that the values give an the particle ratio, 125:875. 

<span>The original parent isotope count was 125 + 875 = 1000. The remaining parent isotope is 125/1000 or 1/8. 1/8 = (1/2)^h, where h is the number of half-lives. </span>

<span>h = log (1/8) ÷ log(1/2) = 3 </span>

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4 0
3 years ago
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4 0
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A cannonball with a mass of 8.3 kg is fired from a cannon that has a mass of 949.3 kg. The cannonball is fired with a speed of 1
Fittoniya [83]
<span>conservation of momentum
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6 0
3 years ago
A solid conducting sphere with radius 0.75 m carries a net charge of 0.13 nC. What is the magnitude of the electric field at a p
Delicious77 [7]

Answer:

Explanation:

given that

Radius =0.75m

Cnet=0.13nC

a. Electric field inside the sphere located 0.5m from the center of the sphere.

The electric field located inside the sphere is zero.

b. The electric field located 0.25m beneath the sphere.

Since the radius is 0.75m

Then, the total distance of the electric field from the centre of the circle is 0.75+0.25=1m

Then

E=kq/r2

K=9e9Nm2/C2

q=0.13e-9C

r=1m

Then,

E= 9e9×0.13e-9/1^2

E=1.17N/C. Q.E.D

3 0
3 years ago
Read 2 more answers
A 480N sphere 40.0cm in radius rolls without slipping 1200cm down a ramp that is inclined at 53 0 with the horizontal. What is t
IgorC [24]

As we know that sphere roll without slipping so there is no loss of energy in this case

so here we can say that total energy is conserved

Initial Kinetic energy + initial potential energy = final kinetic energy + final potential energy

\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2+ mgh'

as we know that ball start from rest

v_i = 0

height of the ball initially is given as

h = Lsin\theta

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also we know that

I = \frac{2}{5}mR^2

also for pure rolling

v = r\omega

also we know that

480 = m*9.8

m = 49 kg

now plug in all data in above equation

480*9.60 + 0 = \frac{1}{2}*49*(0.40*\omega)^2 + \frac{1}{2}*\frac{2}{5}*49*(0.40)^2\omega^2 + 0

4608 = 3.92\omega^2 + 1.568\omega^2

\omega^2 = 839.65

\omega = 29 rad/s

So speed at the bottom of the inclined plane will be 29 rad/s

7 0
3 years ago
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