Derive the kinetic equations for Vmax and KM using the transit time and net rate constant method as discussed in class and follo
wing the attached handout. (Hint: solve for ET/v by summing the inverse net rate constants, then invert to obtain v/ET and put it in the form of kcatS/[KM S]). Remember that if a step is irreversible, the net rate constant for that step is just the rate constant for that step.
1 answer:
Answer:
Rate = vmax k3/k2+k3
Explanation:
The rate of reaction when the enzyme is saturated with substrate is the maximum rate of reaction, is referred to as Vmax.
This is usually expressed as the Km ie. Michaelis constant of the enzyme, an inverse measure of affinity. For practical purposes, Km is the concentration of substrate which permits the enzyme to achieve half Vmax.
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Answer:
Period for 1 revolution is 1.75 seconds
Explanation:
given data
revolutions R = 8
time t = 14 seconds
to find out
What is the period
solution
we know that Period is the time per revolution
so here period formula that is express as
period = =
= 0.57 revolution in one second
so in 1 revolution = seconds
so in 1 revolution = 1.75 seconds
so period for 1 revolution is 1.75 seconds