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2 years ago

Hypersonic scramjet. On March 27, 2004, the United States

Physics

1 answer:

kati45 [8]2 years ago

4 0

25.487 km did the scramjet travel during its 11 second test.

Given that the scramjet travels at a speed seven times that of sound, speed v is equal to 7 x 331 m/s or 2317 m/s.

(A) We require the scramjet's travel time over a distance of

d = 5000 km (5x10^6 m).

Using the formula

time taken = distance traveled/speed,

we can calculate the following:

(5x10^6)/2317 sec

= (5x10^6)/(23175x60) minute

= 5000000/139020 minutes

= 35.97 seconds

As 1 second equals 1/60 of a minute, Therefore, the travel time on Scramjet from San Francisco to New York will be 35.97 minutes.

(B) The distance covered by the Scramjet in 11 seconds must now be determined. as a result,

using speed, distance, and time relation.

Distance = Speed x Time

= 7 x 331 x 11

= 25487 m

Since 1 metre equals 1/1000 of a kilometer, 25487 m of 25.487 km

Learn more about Distance here:

brainly.com/question/15172156

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Alla [95]

Answer:

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Explanation:

In this exercise we are asked about the uncertainty of the momentum of the two carriages

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ΔPₓ = m Δv + v Δm

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ΔPₓ = 0.05 kg m

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now we have the uncertainty of each moment

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Answer:

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