25.487 km did the scramjet travel during its 11 second test.
Given that the scramjet travels at a speed seven times that of sound, speed v is equal to 7 x 331 m/s or 2317 m/s.
(A) We require the scramjet's travel time over a distance of
d = 5000 km (5x10^6 m).
Using the formula
time taken = distance traveled/speed,
we can calculate the following:
(5x10^6)/2317 sec
= (5x10^6)/(23175x60) minute
= 5000000/139020 minutes
= 35.97 seconds
As 1 second equals 1/60 of a minute, Therefore, the travel time on Scramjet from San Francisco to New York will be 35.97 minutes.
(B) The distance covered by the Scramjet in 11 seconds must now be determined. as a result,
using speed, distance, and time relation.
Distance = Speed x Time
= 7 x 331 x 11
= 25487 m
Since 1 metre equals 1/1000 of a kilometer, 25487 m of 25.487 km
Learn more about Distance here:
brainly.com/question/15172156
#SPJ9
