How much work was done to accelerate a 2.2 kg object from rest to 26m/s?

Physics

1 answer:

Makovka662 [10]2 years ago

4 0

Answer:

Explanation:

work done = change in kinetic energy, assuming there are no energy losses.

work done = 1/2 × m × change in v^2

= 1/2 × 2.2 × ( 26^2 - 0^2)

= 1/2 × 2.2 × 676

= 743.6 joules

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