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seropon [69]
3 years ago
9

Astronauts often undergo special training in which they are subjected to extremely high centripetal accelerations. One device ha

s a radius of 15 m and can accelerate a person at 98 m/s2. What is the speed of the astronaut in this device?
Physics
1 answer:
sertanlavr [38]3 years ago
5 0

Answer:

 Speed of astronaut = 38.34 m/s

Explanation:

 Centripetal acceleration is given by the expression, a=\frac{v^2}{r}, where v is the velocity and r is the radius.

 Here centripetal acceleration is given, radius is given, we need to find velocity.

 Centripetal acceleration = 98 m/s²

 Radius = 15 m.

 We have,

     a=\frac{v^2}{r} \\ \\ 98=\frac{v^2}{15} \\ \\ v=38.34m/s

Speed of astronaut = 38.34 m/s

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A van accelerates from 4m/s to 20m/s in 8s. How far does it travel in this time?​
zubka84 [21]

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96 m

Explanation:

Given,

Initial velocity ( u ) = 4 m/s

Final velocity ( v ) = 20 m/s

Time ( t ) = 8 s

Let Acceleration be " a ".

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a = ( v - u ) / t

a = ( 20 - 4 ) / 8

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Let displacement be " s ".

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s = ut + at² / 2

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To solve this problem it is necessary to apply the concepts related to the geometry of a cylindrical tank and its respective definition.

The volume of a tank is given by

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Considering that there are two stages, let's define the initial and final volume as,

V_0 = \frac{\pi d^2}{4}H

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Then we have for the statement that

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Replacing the previous data

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Therefore te change in the height of the water in the tank is 0.37mm

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3 years ago
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