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seropon [69]
3 years ago
9

Astronauts often undergo special training in which they are subjected to extremely high centripetal accelerations. One device ha

s a radius of 15 m and can accelerate a person at 98 m/s2. What is the speed of the astronaut in this device?
Physics
1 answer:
sertanlavr [38]3 years ago
5 0

Answer:

 Speed of astronaut = 38.34 m/s

Explanation:

 Centripetal acceleration is given by the expression, a=\frac{v^2}{r}, where v is the velocity and r is the radius.

 Here centripetal acceleration is given, radius is given, we need to find velocity.

 Centripetal acceleration = 98 m/s²

 Radius = 15 m.

 We have,

     a=\frac{v^2}{r} \\ \\ 98=\frac{v^2}{15} \\ \\ v=38.34m/s

Speed of astronaut = 38.34 m/s

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Answer:

62.64 RPM.

Explanation:

Given that

m= 4.6 g

r= 19 cm

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μk = 0.440.

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Condition just before the slipping starts

The maximum value of the static friction force =Centripetal force

\mu_s\ m g=m\ \omega^2\ r\\ \omega^2=\dfrac{\mu_s\ m g}{m r}\\ \omega=\sqrt{\dfrac{\mu_s\  g}{ r}}\\ \omega=\sqrt{\dfrac{0.82\times 10}{ 0.19}}\ rad/s\\\omega= 6.56\ rad/s

\omega=\dfrac{2\pi N}{60}\\N=\dfrac{60\times \omega}{2\pi }\\N=\dfrac{60\times 6.56}{2\pi }\ RPM\\N=62.64\ RPM

Therefore the speed in RPM will be 62.64 RPM.

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Answer:

this measurement if feet is: 2.624672 ft

Explanation:

Notice that 80 cm can be expressed as 0.8 meters, and In order to convert from meters to feet, one needs to multiply the meter measurement times 3.28084. Therefore:

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