For this, we must know the density of lead. This is 11.36 grams per cubic centimeter. The mass present is 408 grams. Therefore, the volume occupied will be:
408 / 11.36 = 35.9 cubic centimeters. This is the volume of water that will be displaced.
Now, we know that one cubic centimeter is equivalent to one mL. Therefore,
35.9 ml of water will be displaced.
Answer:
time constant will decrease and steady state current will decrease on increasing the resistance
Explanation:
As we know that the EMF of cell is E which is used to connected across a resistor and an inductor.
So we will have

here we know that

now here we have

so if we increase the value of resistance of the wire then the time constant will decrease
and hence it will take less time to reach near the steady state value
also the steady state current will be smaller in that case
Answer:
1.2cm
Explanation:
V=(2ev/m)^1/2
=(2*1.6*10^19 x2500/ 1.67*10^27)^1/2
=6.2x10^5m/s
Radius of resulting path= MV/qB
= 1.67*10^-27x6.92*10^6/1.6*10^-16 x0.6
=0.012m
=1.2cm
Answer:
To know the time ,length area
Answer:
20.7
Explanation:
:0 because basis of the daily occured