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kykrilka [37]
3 years ago
5

Finally, you are ready to answer the main question. Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour miles/hou

r in 2.22 s s starting from rest. Assuming that they have constant acceleration throughout that time, find their acceleration in meters per second squared.
Physics
2 answers:
dolphi86 [110]3 years ago
7 0

Answer:

a = 10.07m/s^2

Their acceleration in meters per second squared is 10.07m/s^2

Explanation:

Acceleration is the change in velocity per unit time

a = ∆v/t

Given;

∆v = 50.0miles/hour - 0

∆v = 50.0miles/hours × 1609.344 metres/mile × 1/3600 seconds/hour

∆v = 22.352m/s

t = 2.22 s

So,

Acceleration a = ∆v/t = 22.352m/s ÷ 2.22s

a = 10.07m/s^2

Their acceleration in meters per second squared is 10.07m/s^2

SCORPION-xisa [38]3 years ago
4 0
<h2>Answer:</h2>

10.1m/s²

<h2>Explanation:</h2>

<em>Using one of the equations of motion as follows;</em>

v = u + at       ----------------------(i)

where;

v = final velocity of the body (Cheetahs) = 50.0 miles/hour

u = initial velocity of the body = 0 (since they start running from rest)

a = acceleration/deceleration

t = time taken for the motion = 2.22s

<em>First convert the final velocity (v) from miles/hour to m/s</em>

Remember that;

1 mile = 1609.34m

1 hour = 60 x 60s = 3600s

Therefore;

50miles/hour = \frac{50miles}{1 hour} = \frac{50*1609.34m}{3600s} = 22.35m/s

=> v = 22.35m/s

<em>Substituting the values of v, u and t into equation (i) gives;</em>

=> 22.35 = 0 + a (2.22)

=> 22.35 = 2.22a

=> a = \frac{22.35}{2.22} = 10.07m/s^{2}

=> a = 10.1m/s² (to 1 decimal place)

Therefore the acceleration in m/s² is 10.1

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Air expands adiabatically in a piston–cylinder assembly from an initial state where p1 = 100 lbf/in.2, v1 = 3.704 ft3/lb, and T1
lutik1710 [3]

Answer:

Final temperature is equal to 1291.63°R  

Explanation:

given,

p₁ = 100 lb f/in²,               v₁ = 3.704 ft³/lb,           and T₁ = 1000 °R

p₂ = 30 lb f/in²                 n = 1.4

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we know for poly tropic process

p vⁿ = constant

p₁ v₁ⁿ = p₂ v₂ⁿ

100 × 3.704¹°⁴ = 30 × v₂¹°⁴

v₂ = 8.753 ft³/lb

work done for poly tropic process

W = \dfrac{p_1v_1-p_2v_2}{n-1}

    = \dfrac{100\times 3.704-30\times 8.753}{1.4-1}

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W = \dfrac{269.525}{5.40395} Btu/lb

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in the piston cylinder arrangement air is expanding acrobatically

Δ q = Δu + w

Δ u = - w

0.171(T₂ - T₁) = -49.87

0.171(T₁ - T₂) = -49.87

0.171 T₂ = 0.171 × 1000 + 49.87

T₂ = 1291.63 °R

Final temperature is equal to 1291.63°R  

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Which is a characteristic that makes electromagnetic waves and water waves different
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We know that a wave is a disturbance that transfers energy through matter or space There are two main types of waves: Mechanical and Electromagnetic. Water waves are mechanical. A mechanical wave is an oscillation of matter to transfers energy, but you always need a medium (substance such as: solid, liquid, gas, plasma) to transport it. The medium for water waves is, in fact, the water. For example, ripple in water is a surface wave. On the other hand, electromagnetic waves don't need a medium to transport, they can do it through the empty space. Then, this is the major characteristic that makes these two types of waves different.

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A car turns a certain curve of radius 24.98 m with constant linear speed of
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Answer:

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Explanation:

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