Let's say that y is the weight of the mother and x is the weight of the baby.
We know that the baby is 7437 pounds less than the mother, which means you need to add 7437 pounds to the baby's weight to get the mother's.
We can show it like this:
x+7437=y.
We know what the baby's weight is (1400 lbs), so just sub it in:
1400+7437=y
y=8837 lbs
The mom weighs 8837 pounds.
Answer:
D
Step-by-step explanation:
27÷3=9
Answer:
why?? ksi ko nhi pta wo kab jai ga...
<u>Answer:
</u>
Two required integers are 5 and 10.
<u>
Solution:
</u>
Given that a positive integer is twice another. The sum of the reciprocals of the positive integers is ![\frac{3}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B10%7D)
We have to find the two integers.
Let assume that one integer = x
Since another integer is twice of first one, so second integer = 2x
Reciprocal of first integer = ![\frac{1}{x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%7D)
Reciprocal of first integer = ![\frac{1}{2x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2x%7D)
Given that sum of reciprocal = ![\frac{3}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B10%7D)
![\frac{1}{x}+\frac{1}{2 x}=\frac{3}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%7D%2B%5Cfrac%7B1%7D%7B2%20x%7D%3D%5Cfrac%7B3%7D%7B10%7D)
On solving above equation for x,
![\frac{2+1}{2 x}=\frac{3}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B2%2B1%7D%7B2%20x%7D%3D%5Cfrac%7B3%7D%7B10%7D)
![\frac{3}{2 x}=\frac{3}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%20x%7D%3D%5Cfrac%7B3%7D%7B10%7D)
2x=10
x=5
First integer = x = 5
Second integer = 2x = 10
Hence two required integers are 5 and 10.
There would be an 85% change, you just add then divide them and you get 85% as your answer.