Question

What mass of HgO is required to produce 0.692 mol of O2?2HgO(s) -> 2Hg(l) + O2(g)

Answer 1

The answer for the following problem is mentioned below.

• Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule

Explanation:

Given:

no of moles of the oxygen gas = 0.692

Also given:

2 HgO  → 2 Hg + $O_{2}$

where,

HgO represents mercuric oxide

Hg represents mercury

$O_{2}$ represents oxygen

To calculate:

Molar mass of HgO:

Molar mass of HgO = 216 grams

molar mass of mercury (Hg) = 200 grams

molar mass of oxygen (O) =16 grams

HgO = 200 +16 = 216 grams

We know;

       2×216 grams of HgO   →  1 mole of oxygen molecule

             ?                              →  0.692 moles of oxygen molecule

       

          = $\frac{2*216*0.692}{1}$

      = 298.944 grams of HgO

Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule

Answer 2

Answer:

299.76g of HgO

Explanation:

2HgO(s) -> 2Hg(s) + O2(g)

We check and we see that the equation is balanced.

2 moles of HgO dissociates to produce 1 mole of O2

Mole ratio is 2:1

2 moles of HgO produces 1 mole of O2,

Then, x moles of HgO will produce 0.692mol O2

x=(2×0.692)/1

x=1.384

Therefore, 1.384 moles of HgO will produce 0.692mole of O2

mass of 1.384 moles of HgO = number of moles × molar mass of HgO

Number of moles = 1.384

Molar mass of HgO = 216.59g/mol

mass = 1.384×216.59 =299.76 g

Therefore, 299.76g of HgO will produce 0.692 moles of O2