<u>Answer:</u> The standard Gibbs free energy of the reaction is -15.8 kJ/mol
<u>Explanation:</u>
Relation between standard Gibbs free energy and equilibrium constant follows:
where,
= Standard Gibbs free energy = ?
R = Gas constant = 
T = temperature = 298 K
= equilibrium constant = 581
Putting values in above equation, we get:
Conversion factor used: 1 kJ = 1000 J
Hence, the standard Gibbs free energy of the reaction is -15.8 kJ/mol
Answer:
Alloys are often stronger and less active than pure metals. Alloys have higher melting point than pure metals.
Answer
is: the molar mass of a covalent compound is 90.4 g/mol.
<span>
m(compound) = 0.486 g.
m(water) = 25 mL </span>· 1 g/mL = 25 g ÷ 1000 g/kg = 0.025 kg.<span>
ΔT = 0°C - (-0.40°C) = 0.40°C.</span>
Kf(H₂O) = 1.86°C/m.
M(compound) = Kf · m(compound<span>) /
m(water) · ΔT.
M</span>(compound)<span>= 1.86°C/m · 0.486 g /
(0.025 kg · 0.4°C).
M</span>(compound) = 90.4 g/mol.
Answer:
1370moles
Explanation:
Given parameters:
Number of molecules in methane = 8.25 x 10²⁶molecules
Unknown:
Number of moles of methane = ?
Solution:
A mole of any substance contains the Avogadro's number of particles which is 6.02 x 10²³molecules;
6.02 x 10²³ molecules is contained in 1 mole of a substance
8.25 x 10²⁶molecules of methane will contain 
= 1370moles
It is the tendency of the electrons in the outermost atomic orbital to remain unionized or unshared in compounds of post transition metals...
