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iVinArrow [24]
3 years ago
5

How much total wrapping paper does it take to wrap two gifts: one with the dimensions of 6 cm by 10 cm by 9.5 cm and the other w

ith dimensions 14 cm by 17.25 cm by 15 cm. If we were to fill the boxes with packing peanuts, how many total cubic centimeters would we need of packaging peanuts?
Mathematics
1 answer:
zhuklara [117]3 years ago
5 0

Answer:

gift 1:

424 cm^2

570 cm^3

gift 2:

1420.5 cm^2

3622.5 cm^3

Step-by-step explanation:

We have to calculate the surface area of these gifts in order to know the amount of wrapping paper.

The formula for the surface area is:

A = 2*ab + 2*ac + 2*bc

Gift 1:

A = 2*6*10 + 2*6*9.5 + 2*10*9.5

A = 424 cm^2

That means that gift 1 needs 424 cm^2 of wrapping paper

Gift 2:

A = 2*14*17.25 + 2*14*15 + 2*17.25*15

A = 1420.5 cm^2

That means that gift 2 needs 1420.5 cm^2 of wrapping paper

Now, to calculate the cubic centimeters of packaging peanuts, we calculate the volume, the volume has as formula:

V = a*b*c  

Gift 1:

V = 6*10*9.5  

V = 570 cm^3

This means that gift 1 needs 570 cm^3 of packaging peanuts

Gift 2:

V = 14*17.25*15  

V = 3622.5 cm^3

That means that gift 2 needs 3622.5 cm^3 of packaging peanuts

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If B is the midpoint of AC, then |AB| = |AC|.
|AB| = 3x + 2
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Therefore we have the equation:
3x + 2 = 5x - 10     |subtract 2 from both sides
3x = 5x - 12      |subtract 5x from both sides
-2x = -12      |divide both sides by (-2)
x = 6

Read more on Brainly.com - brainly.com/question/11324096#readmore
4 0
3 years ago
Help with my homework <br> Evaluate the exponent expression for a = 1 and b = –2.
Snowcat [4.5K]

Answer:

  -1/16

Step-by-step explanation:

Put the values where the variables are and do the arithmetic.

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A calculator can help you figure this out.

7 0
2 years ago
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adell [148]

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I am stupid too, so forgive me if I am wrong.ಥ_ಥ

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4 0
3 years ago
Find the particular solution that satisfies the differential equation and the initial condition.
Vesnalui [34]

Answer:

1) y =4x^2 +7

2) y =7s^2 -3s^4 +181

Step-by-step explanation:

Assuming that our function is y = f(x) for the first case and y=f(s) for the second case.

Part 1

We can rewrite the expression like this:

\frac{dy}{dx} =8x

And we can reorder the terms like this:

dy = 8 x dx

Now if we apply integral in both sides we got:

\int dy = 8 \int x dx

And after do the integrals we got:

y = 4x^2 +c

Now we can use the initial condition y(0) =7

7 = 4(0)^2 +c, c=7

And the final solution would be:

y =4x^2 +7

Part 2

We can rewrite the expression like this:

\frac{dy}{ds} =14s -12s^3

And we can reorder the terms like this:

dy = 14s -12s^3 dx

Now if we apply integral in both sides we got:

\int dy = \int 14s -12s^3 ds

And after do the integrals we got:

y = 7s^2 -3s^4 +c

Now we can use the initial condition y(3) =1

1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181

And the final solution would be:

y =7s^2 -3s^4 +181

7 0
3 years ago
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Semmy [17]

Answer:

f(x) = 10x + 13

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Step-by-step explanation:

y = 10x + 13

f(x) = 10x + 13

Function f(7) = 10(7) + 13

Function f(7) = 83

6 0
3 years ago
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