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emmainna [20.7K]
3 years ago
10

Hey all, i’m going to do a long questions so i hope y’all don’t mind answering?

Mathematics
1 answer:
abruzzese [7]3 years ago
8 0

Answer:

81

Step-by-step explanation:

1st History test: 73

2nd History test: 77

3rd History test: 81

4th History test: 85

5th History test: 89

73+77+81+85+89 = 405

405/5 = 81

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Solve the equation using the quadratic formula 3x^2 =2(2x+1)
Nadusha1986 [10]
Step 1: Make equation equal to Zero

3x^2 = 4x + 2


3x^2 - 4x - 2 


Step 2: use equation

a= 3 b = -4 c= -2 

after plugging in answer should be

(2 + or - sqrt 10) / 3 


3 0
3 years ago
Read 2 more answers
The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What
Simora [160]

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that \mu = 64.4, \sigma = 2.91

Sample of 50 women

This means that n = 50, s = \frac{2.91}{\sqrt{50}}

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}

Z = 1.46

Z = 1.46 has a p-value of 0.9279

1 - 0.9279 = 0.0721

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

8 0
2 years ago
Which one is it , help me on this please please please please please please please
snow_tiger [21]

Answer:

D

Step-by-step explanation:

7^-2 = 1/7^2

The negative means you flip it

1/7^2 times 7^6 is 7^6/7^2 (just multiply).

using rules of exponents, 7^6/7^2 is 7^4 (just subtract 2 from 6)

D is the only one that equals 7^4, as 2 times 2 is 4.

4 0
3 years ago
PLEASE SOMEONE HELP ME ASAP!!!!!ANYONE PLEASE!!!!
Natasha2012 [34]
Answer: B.$43.95


Explanation: 15% of $293 is $43.95
6 0
3 years ago
Read 2 more answers
6a+5b=4.54<br> 3a+7b=3.17
Liula [17]

Answer:

7.71

Step-by-step explanation:

add it up

6 0
3 years ago
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