Answer:
S = V0 t + 1/2 a t^2
S = 5 m/s * 300 s + 1/2 * 1.2 m/s * (300 s^2)
S = 1500 m + .6 * 90000 m = 55,500 m
Check: V0 = 5 m/s
V2 = V0 + a t = 5 + 1.2 * 300 = 365 m/s
Vav = (V1 + V2) / 2 = (5 + 365) / 2 = 185 m/s (note uniform motion)
S = 185 * 300 = 55,500 m
We calculated V2 above at 365 m/s the speed after 300 sec
Answer:
The answer is the object weighs 5 so 3-5 is 2
Explanation:
I took this test
Answer:

Explanation:
Given:
- charge on the alpha particle,

- mass of the alpha particle,

- strength of a uniform magnetic field,

- radius of the final orbit,

<u>During the motion of a charge the magnetic force and the centripetal forces are balanced:</u>


where:
v = velocity of the alpha particle



Here we observe that the velocity of the aprticle is close to the velocity of light. So the kinetic energy will be relativistic.
<u>We firstly find the relativistic mass as:</u>



now kinetic energy:



The letter "B" is used for magnetic field
(3) 8.3 N/kg. The gravitational field strength at a point is the force per unit mass exerted on a mass placed at that point. So at the point where the Hubble telescope is, it is (9.1 x 10^4)N/(1.1 x 10^4 kg) = 8.3 N/kg
Fam