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4 years ago

5

a car moving at 11 m/s crashes into an obstacle and stops in 0.26s. compute the Force that a seatbelt exerts on a 21-kg child to

bring him/her to a stop

1 answer:

Natalka [10]4 years ago

4 0

Answer:

890 N

Explanation:

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (11 m/s − 0 m/s) / 0.26 s

a = 42.3 m/s²

Force is mass times acceleration.

F = ma

F = (21 kg) (42.3 m/s²)

F ≈ 890 N

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Explanation:

From the question we are told that

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Here E the the energy of the spring which is increasing and this is mathematically represented as

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