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3 years ago

What are the variables do you think to be considered to determine the acceleration of an object?

1 answer:

8 0

The two variables that you need to measure are velocity (and any changes in velocity) and time intervals (where velocity changes)

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Problem 1: Spherical mirrorConsider a spherical mirror of radius 2 m, and rays which go parallel to the optic axis. What is thep

SIZIF [17.4K]

Answer:

1) iii i= 1m, 2) iii and iv, 3) i = f₂ (L-f₁) / (L - (f₁ + f₂))

Explanation:

Problem 1

For this problem we use two equations the equations of the focal distance in mirrors

f = r / 2

f = 2/2

f = 1 m

The builder's equation

1 / f = 1 / o + 1 / i

Where f is the focal length, "o and i" are the distance to the object and the image respectively.

For a ray to arrive parallel to the surface it must come from infinity, whereby o = ∞ and 1 / o = 0

1 / f = 0 + 1 / i

i = f

i = 1 m

The image is formed at the focal point

The correct answer is iii

Problem 2

For this problem we have two possibilities the lens is convergent or divergent, in both cases the back face (R₂) must be flat

Case 1 Flat lens - convex (convergent)

R₂ = infinity

R₁ > 0

Cas2 Flat-concave (divergent) lens

R₂ = infinity

R₁ <0

Why the correct answers are iii and iv

Problem 3

For a thick lens the rays parallel to the first surface fall in their focal length (f₁), this is the exit point for the second surface whereby the distance to the object is o = L –f₁, let's apply the constructor equation to this second surface

1 / f₂ = 1 / (L-f₁) + 1 / i

1 / i = 1 / f₂ - 1 / (L-f₁)

1 / i = (L-f₁-f₂) / f₂ (L-f₁)

i = f₂ (L-f₁) / (L - (f₁ + f₂))

This is the image of the rays that enter parallel to the first surface

6 0

4 years ago

1The density of an of an object with a volume of 60.0 and mass of 400.0g is______

Kobotan [32]

D is the answer
To get the density you divide mass by volume
So the equation is 400/60=d

4 0

3 years ago

Two cars, a Porsche Boxster convertible and a Toyota Scion xB, are traveling at constant speeds in the same direction. Suppose,

fenix001 [56]

Answer:

It will take 29.31 seconds for the Boxster to catch the Scion

Explanation:

Given the data in the question;

lets say Toyota Scion xB is car A and Porsche Boxster convertible is B and Toyota Scion xB is car A

the distance travelled by car A is

x = $V_{A}$ × t

where $V_{A}$ is the speed of the car and t is time

the distance travelled by car B before reaching car A will be;

x + x₀ = $V_{B}$ × t

Now lets replace x by $V_{A}$ × t

( $V_{A}$ × t) + x₀ = $V_{B}$ × t

x₀ = ( $V_{B}$ × t) - ( $V_{A}$ × t)

x₀ = t ( $V_{B}$ - $V_{A}$ )

t = x₀ / ( $V_{B}$ - $V_{A}$ )

so we substitute

t = 170 m / (24.4 - 18.6)

t = 170 / 5.8

t = 29.31 s

Therefore; it will take 29.31 s for the Boxster to catch the Scion

8 0

3 years ago

The unit of energy is a derived unit why

olga2289 [7]

Answer:

The unit of energy is joule which depends upon the fundamental unit kg, m and sec. So, the unit of energy is a derived unit.

Explanation:

7 0

3 years ago

Read 2 more answers

Calculate the vapor pressure for a mist of spherical water droplets of radius 3.70×10−8m surrounded by water vapor at 298 K. The

poizon [28]

Answer:

The vapor pressure for a mist is $P= 25.92\ Torr$

Explanation:

From the question we are given that

The radius is $r = 3.70 *10^{-8} m$

The temperature is $T = 298K$

The vapor pressure of water $P_o = 25.2\ Torr$

The density of water is $\rho = 998 kg.m^{-3}$

The surface tension of water is $\sigma = 71.99 m N \cdot m^{-1}$

Generally the equation of that is mathematically represented as

$ln (\frac{P}{P_0} ) = \frac{2 \sigma M}{r \rho RT}$

Where P is the vapor pressure for mist

R is the ideal gas constant = 8.31

making P the subject in the formula

$P = e^ {\frac{2 \sigma M}{r \rho RT}} * P_0$

$= e^{\frac{2 *(0.07199)(0.018)}{(3.70*10^{-8})(998)(8.31)(298)} } * 25.2$

$P= 25.92Torr$

4 0

3 years ago