Answer:
If a body is moving with uniform velocity, acceleration is zero. So net force acting on it will be also zero. But the body has energy due to its constant motion.
The distance r between the pions when the criteria are satisfied is 1.45 × 10⁻¹⁶ m
If we consider the potential energy (U) between the pions, then (U) can be expressed as:
Given that at some instance, the potential energy becomes negligible compared to the final K.E.
As such the conservation of the total energy in the system can be given as:
Again, if we consider the ratio of the potential energy to the kinetic energy to be about 0.01, then:
∴
Equating both equations (1) and (2) together, we have:
where:
- r = distance
- k = Columb's constant
- q = charge on a proton
- m_o = rest mass of each pion in the previous question
- c = velocity of light
- = calculated velocity of proton in the previous question
Replacing their values in the above equation, the distance (r) between the pions is calculated as:
distance (r) = 1.45 × 10⁻¹⁶ m
Therefore, we can conclude that the distance r between the pions when the criteria are satisfied is 1.45 × 10⁻¹⁶ m
Learn more about electric potential energy here:
brainly.com/question/21808222?referrer=searchResults
Hi there!
Use the following kinematic equation to solve:
vf² = vi² + 2(ad)
Since the initial velocity is 0 m/s because it started at rest, we can eliminate this part of the equation:
vf² = 2ad
Plug in the given acceleration and distance:
vf² = 2(9.8)(16)
vf ≈ 17.7. The correct answer is C.
6.6 miles I think hope this is the right answer.