Hi there!
We can begin by finding the acceleration of the block.
Use the kinematic equation:
The block starts from rest, so:
Now, we can do a summation of forces of the block using Newton's Second Law:
mb = mass of the block
T = tension of string
Solve for tension:
Now, we can do a summation of torques for the wheel:
Rewrite:
We solved that the linear acceleration is 1.5 m/s², so we can solve for the angular acceleration using the following:
Now, plug in the values into the equation:
When trying to describe how an object falls, Newton found that the speed of the object increased in every split second and no mathematics currently used to describe the object at any moment in time.
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Answer:
Explanation:
radius of gyration of wheel k then
k² = r²/2
r² = 2 k²
r = √2 k
= 1.414 x .3 m
r = .4242 m
Moment of inertia of wheel
= mass x radius of gyration ²
= 25 x .3 x .3
= 2.25 kg m²
Friction force acting on it ( sliding )
= μmg , μ being coefficient of kinetic friction
This friction force will create linear acceleration in forward direction
Acceleration produced
= μg
= .6 x 9.8
= 5.88 m / s ²
This will also rotate the wheel , angular acceleration being
linear acceleration / radius
= 5.88 /.4242
= 13.86 radian / s²
Answer:
A.) V = 14 m/s
B.) h = 36.6 m
Explanation:
Given the formula v = √2gh
where g = 9.8m/sec^2 is the acceleration due to gravity.
A.) Determine the impact velocity for an object dropped from a height of 10 m.
Substitute height h in the given formula
V = √2gh
V = √2 × 9.8 × 10
V = √196
V = 14 m/s
b. Determine the height required for an object to have an impact velocity of 26.8 m/sec (~ 60 mph). Round to the nearest tenth of a meter.
Substitute the velocity in the given formula and make height h the subject of formula.
26.8 = √2 × 9.8 × h
Square both sides
718.24 = 19.6h
h = 718.24 / 19.6
h = 36.64 m
h = 36.6 m
