C ,vehicles get stuck in the middle of an intersection
Answer:
(a) The magnitude of the electric dipole moment is 1.68 x 10⁻¹⁴ C.m
(b) The difference between the potential energies ΔU, is 4.6704 x 10⁻¹¹ J
Explanation:
Given;
magnitude of charge, q = 2 nC = 2 x 10⁻⁹ C
distance of separation, d = 8.4 μm = 8.4 x 10⁻⁶ m
strength of electric field, E = 1390 N/C
(a) the magnitude of the electric dipole moment
p = qd
p = (2 x 10⁻⁹ C)(8.4 x 10⁻⁶ m)
p = 1.68 x 10⁻¹⁴ C.m
(b) the difference between the potential energies for dipole orientations parallel and anti-parallel to E
ΔU = U(180) - U(0)
ΔU = 2pE
ΔU = 2(1.68 x 10⁻¹⁴ )(1390)
ΔU = 4.6704 x 10⁻¹¹ J
One problem with weight training as a way to improve overall health is that the results of a weight-training program are not measurable.
B.False
Answer:
Explanation:
Force on a moving charge is given by the following relation
F = q ( v x B )
for proton
q = e , v = vi , B = Bk
F = e ( vi x Bk )
= Bev - j
= - Bevj
The direction of force is along negative of y axis or -y - axis.
for electron
q = - e , v = vi , B = Bk
F = - e ( vi x Bk )
= - Bev - j
= Bevj
The direction of force is along positive of y axis or + y - axis.
Answer:
The force is 272.73 newtons
Explanation:
We're going to use impulse-momentum theorem that states impulse is the change on the linear momentum this is:
(1)
Impulse is also defined as average force times the time the force is applied:
(2)
By (2) on (1):
solving for 
:
(3)
We already know Δt is equal to 0.22 s, all we should do now is to find 
and put on (3) (
the initial momentum and 
the final momentum). Linear momentum is defined as 
, using that on (3):
(4)
Velocity (v) are vectors so direction matters, if positive direction is the right direction and negative direction left 
and 
so (4) becomes:
(5)
Using (5) on (3):
