Answer:
Change in temperature ∆(tita) is 266.097°C
Explanation:
Ok kinectic energy = 1/2MV²
5.4 grams =( 5.4/1000) kilogram
Kinectic energy =( 1/2 )*(5.4/1000)*261²
Kinectic energy = 183.9267 joules
If kinetic energy = thermal energy
183.9267 joules = mc∆(tita)
Where ∆(tita) = change in temperature
And c = 128 J/kg
∆(tita) = 183.9267/((5.4/1000)*128)
∆(tita) = 266.097
∆(tita) = 266.097°C
To solve the problem, use Kepler's 3rd law :
T² = 4π²r³ / GM
Solved for r :
r = [GMT² / 4π²]⅓
but first covert 6.00 years to seconds :
6.00years = 6.00years(365days/year)(24.0hours/day)(6...
= 1.89 x 10^8s
The radius of the orbit then is :
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.89 x 10^8s)² / 4π²]⅓
= 6.23 x 10^11m
Answer:
deep scattering layer
Explanation:
I hope this is right, I kind of learned this like a year ago
Answer:
wrestling
Explanation:
You might have a team but it's only you and the other person on the mat so you are alone
