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Artist 52 [7]
2 years ago
5

An asteroid orbits the Sun at an average distance of a= 4 AU. How long does it take to orbit the Sun?Use Kepler’s Third Law(p2=

a3) to calculate the answer.
Physics
1 answer:
marta [7]2 years ago
3 0

Answer:

7982 seconds

Explanation:

Parameters given:

Distance of asteroid, a = 4 AU = 5.984 * 10^8 m

Mass of sun, M = 1.9891 * 10^30 kg

Orbital period, P, is given as:

P² = (4π²a³) /(GM)

Where G = 6.6774 * 10^(-11) m³/kgs²

P² = [4 * π² * (5. 984 * 10^8)³]/(6.674 * 10^(-11) * 1.9891 * 10^30)

P² = (8.459 * 10^27)/(1.328 * 10^20)

P² = 6.372 * 10^7

=> P = 7982 seconds

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3 years ago
2. What is the standard value of acceleration due to gravity or "g"?
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Answer:

The standard acceleration due to gravity (or standard acceleration of free fall), sometimes abbreviated as standard gravity, usually denoted by ɡ0 or ɡn, is the nominal gravitational acceleration of an object in a vacuum near the surface of the Earth. It is defined by standard as 9.80665 m/s2 (about 32.17405 ft/s2).

Explanation:

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3 years ago
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A grasshopper hops along a level road. on each hop, the grasshopper launches itself itself at an angle of 45 degrees. and achiev
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Answer: 1.9 m/s


Explanation:


1) Data:

height, y = 0

range, x = 0.77m

angle, α = 45°

question, horizontal velocity, Vox = ?


2) Physical principles and formulas

Projectile motion.

y=V_{0y}t-gt^{2} /2\\ \\ x=V_{0x}t\\ \\ V_{0y}=V_0sin\alpha \\ \\ V_{0x}=V_0cos\alpha


3) Solution

0.77=V_0cos(45)t\\ t=0.77/(V_0cos(45))


y=0=V_0sin(45)t-gt^{2} /2


Factor


0=t[V_0sin(45)-gt/2]


Discard t = 0 and solve for the other factor:


gt/2=V_0sin(45)\\ \\  V_0= gt/(2sin(45))=9.81[0.77/V_{0}cos(45)]/[2sin(45)]\\ \\ V_0^2=9.81[0.77/(2cos(45)sin(45)=9.81[0.77/sin(90)]=7.55\\ \\ V_0}=\sqrt{7.55} =2.8


Find Vx:


Vx=V_{0x}=V_{0}cos(45)=2.75(\sqrt{2} /2]=1.9


Vx = 1.9m/s ← answer

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2 years ago
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What are minerals made of a single element called?
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3 0
3 years ago
find the gravitational force this shell exerts on a 1.60 kg point mass placed at the distance 5.01 m from the center of the shel
RideAnS [48]

The gravitational force of the shell exerts is 4.25m x 10¯¹² N.

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses of objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

m1 = 1.6 kg

m2 = m

R = 5.01 m

By substituting the following parameters, we get

F = G.m1.m2 / R²

F = 6.674 × 10¯¹¹  . 1.6 . m / 5.01²

F = 4.25m x 10¯¹² N

where m is the mass of the shell

For more on gravitational force at: brainly.com/question/19050897

#SPJ4

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1 year ago
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