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Artist 52 [7]
3 years ago
5

An asteroid orbits the Sun at an average distance of a= 4 AU. How long does it take to orbit the Sun?Use Kepler’s Third Law(p2=

a3) to calculate the answer.
Physics
1 answer:
marta [7]3 years ago
3 0

Answer:

7982 seconds

Explanation:

Parameters given:

Distance of asteroid, a = 4 AU = 5.984 * 10^8 m

Mass of sun, M = 1.9891 * 10^30 kg

Orbital period, P, is given as:

P² = (4π²a³) /(GM)

Where G = 6.6774 * 10^(-11) m³/kgs²

P² = [4 * π² * (5. 984 * 10^8)³]/(6.674 * 10^(-11) * 1.9891 * 10^30)

P² = (8.459 * 10^27)/(1.328 * 10^20)

P² = 6.372 * 10^7

=> P = 7982 seconds

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Answer:D. λfilm/4

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The film thickness will need to be increased by λfilm/4 for it to be able to give a destructive interference.

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When the activation energy of an exothermic reaction decreases at a given temperature, the reaction rate increases because the _
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Use V=Voe^-t/RC and T=RC to derive T1/2=Tln2
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3 years ago
The Hoover dam is a hydroelectric power plant that converts the energy of falling water into electricity. Which of the following
vlabodo [156]

The correct answer to the question is : B) The weight of the water, and C) The height of the water.

EXPLANATION :

Before coming into any conclusion, first we have to understand potential energy of a body.

The potential energy of a body due to its position from ground is known as gravitational potential energy.

The gravitational potential energy is calculated as -

                      Potential energy P.E = mgh

 Here, m is the mass of the body, and g is the acceleration due to gravity.

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3 0
3 years ago
Read 2 more answers
A net force of –8750N is used to stop of 1250.kg car travelling 25m/s. What braking distance is needed to bring the car to a hal
Karolina [17]

Answer:

d = 44.64 m

Explanation:

Given that,

Net force acting on the car, F = -8750 N

The mass of the car, m = 1250 kg

Initial speed of the car, u = 25 m/s

Final speed, v = 0 (it stops)

The formula for the net force is :

F = ma

a is acceleration of the car

a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2

Let d be the breaking distance. It can be calculated using third equation of motion as :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m

So, the required distance covered by the car is 44.64 m.

4 0
3 years ago
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