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4 years ago

Which of the following observations indicates that an object is falling at terminal velocity?

Physics

1 answer:

vitfil [10]4 years ago

5 0

Answer: D

Explanation:

When an object falls gravity is pulling down on it and is picking up speed, but as it gains speed air resistance becomes a faster. Air resistance increases with speed. And that force keeps it from accelerating eventually the object will pick up speed such that the force due to air resistance will keep it from getting any more speed at that point force due to air resistance is equal to its weight (mg) and the net force is equal to zero so it won’t accelerate any more at that point it is said to be moving in terminal velocity.

When an object has reached terminal velocity, it will have a constant velocity

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Which type of scientific statement describes a proven fact about how things function in nature? a law a theory an inquiry a hypo

WITCHER [35]

Which type of scientific statement describes a proven fact about how things function in nature? a law a theory an inquiry a hypothesis

The key word is "proven fact". The answer is: a law.

8 0

4 years ago

Read 2 more answers

Which one of the following is not a derived quantity a)speed b)velocity c)time d)force

qaws [65]

Answer:

c) time

Explanation:

time is a fundamental quantity from which other quantities are derived

5 0

3 years ago

A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coi

nlexa [21]

In order to find the radius of the coin, we need to use:

Ac = V^2 r

In which,
Ac = acceleration of the coin = 2.2 m/s^2
V= rotational Speed = (18/12) * 2πr
r= Radius

so,
2.2 = 9(π^2)(r^2) / r
= 9(π^2)r

r = 2.2 / 9(π^2) = 0.02476740044 m . . .or you can rounded it up to 0.025 m

4 0

3 years ago

Read 2 more answers

A train accelerates from a station with a = 1.841m/s ? Upon reaching a speed of 23.52m/s the train travels at a constant velocit

scZoUnD [109]

Answer:

63.29s

Explanation:

Firstly calculate the time taken to reach 23.52m/s

;use the formula...v = u + at

23.52 = 0 + 1.841t

then obtain...t = 12.78s

Then calculate the time for the last part of the journey...where the train slows down...

use the formula that is above...

0 = 23.52 - 2t...(negative for deceleration)

then obtain....t = 11.76s

Then we know that the total area under the graph of u against t..is equal to 1200m

For the first triangle(first part of the journey...where the train accelerates)

(23.52 × 12.78)÷2 = 150.3m

Then for the constant velocity part...a rectangle...

23.52 × f.....where f represents the time taken by the train having constant velocity.

...= 23.52fm

Then for the last part of the journey...the deceleration part..a triangle

(23.52 × 11.76)÷ 2 = 138.3m

Then....we add all the obtained distances and equate to 1200m so that we can obtain time (f)

138.3 + 150.3 + 23.52f = 1200

where f = 38.75s

Then total time for the whole journey of the train...

38.75 + 11.76 + 12.78

;Ans = 63.29s

3 0

3 years ago

Which would be a common-sense practice in a lab environment?

algol13

Using safe research practices would be a very good common-sense practice in a lab environment.

6 0

3 years ago