Question

Calculate the amount of grams of water that was used when 5525J of energy was used to boil this amount of water.

Answer 1

Answer:

2.445 g

Explanation:

Step 1: Given and required data

• Energy in the form of heat required to boil the water (Q): 5525 J

• Latent heat of vaporization of water (∆H°vap): 2260 J/g

• Mass of water (m): ?

Step 2: Calculate the mass of water

We will use the following expression.

Q = ∆H°vap × m

m = Q / ∆H°vap

m = 5525 J / (2260 J/g)

m = 2.445 g