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ValentinkaMS [17]
3 years ago
12

Calculate the amount of grams of water that was used when 5525J of energy was used to boil this amount of water.

Chemistry
1 answer:
djverab [1.8K]3 years ago
4 0

Answer:

2.445 g

Explanation:

Step 1: Given and required data

  • Energy in the form of heat required to boil the water (Q): 5525 J
  • Latent heat of vaporization of water (∆H°vap): 2260 J/g
  • Mass of water (m): ?

Step 2: Calculate the mass of water

We will use the following expression.

Q = ∆H°vap × m

m = Q / ∆H°vap

m = 5525 J / (2260 J/g)

m = 2.445 g

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Answer: The density of chloroform is 1.47 g/mL

Explanation : Given,

Volume = 40.5 mL

Mass of cylinder = 85.16 g

Mass of cylinder and liquid = 145.10 g

First we have to calculate the mass of liquid (chloroform).

Mass of liquid = Mass of cylinder and liquid - Mass of cylinder

Mass of liquid = 145.10 g - 85.6 g

Mass of liquid = 59.5 g

Now we have to calculate the density of liquid (chloroform).

Formula used:

Density=\frac{Mass}{Volume}

Now putting g all the given values in this formula, we get:

Density=\frac{59.5g}{40.5mL}

Density=1.47g/mL

Therefore, the density of chloroform is 1.47 g/mL

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3 years ago
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Answer:

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Explanation:

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3 years ago
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The reaction of hydrogen gas and iron oxide is described by the chemical equation below. 3H2+Fe2O3→2Fe+3H2O How many moles of ir
ELEN [110]

Answer:

2.2 moles of Fe will be produced

Explanation:

Step 1: Data given

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Step 2: The balanced equation

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For 3.3 moles H2 we'll have 2/3 * 3.3 = 2.2 moles Fe

2.2 moles of Fe will be produced

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