Answer:
The answer to your question is: 2 grams of methane
Explanation:
Data
V = 9.15 l
P = 1.77 atm
T = 57° C = 330 °K
Ar mass = 19 g
CH4 mass = ?
Formula
PV = nRT
Process



n = 0.6
Argon
40 g of Ar -------------------- 1 mol
19 g --------------------- x
x = 0.475 mol of Ar
moles of CH4 = 0.6 - 0.475
= 0.125
Methane
16 g of CH4 --------------- 1mol
x ---------------- 0.125 mol
x = 2 grams
Answer:
Vapor pressure of solution is 78.2 Torr
Explanation:
This is solved by vapor pressure lowering:
ΔP = P° . Xm . i
Vapor pressure of pure solvent (P°) - vapor pressure of solution = P° . Xm . i
NaCl → Na⁺ + Cl⁻ i = 2
Let's determine the Xm (mole fraction) These are the moles of solute / total moles.
Total moles = moles of solvent + moles of solute
Total moles = 0.897 mol + 0.182 mol → 1.079 mol
0.182 / 1.079 = 0.168
Now we replace on the main formula:
118.1° Torr - P' = 118.1° Torr . 0.168 . 2
P' = - (118.1° Torr . 0.168 . 2 - 118.1 Torr)
P' = 78.2 Torr
Answer:
Elements are classified into- metals – Nonmetals- Metalloids – Noble gases. State which of A, B, C, D is a:
1) Metallic element
2) Non-metallic element
3) Metalloid
4) Noble gas.
A) Is non-malleable, non-ductile and a poor conductor of electricity
B) Has lustre, is malleable and ductile and a good conductor of electricity
C) Is unreactive and inert and present in traces in air
D) Shows properties of both metals and nonmetals
Explanation:
Answer:
92.04%
Explanation:
Given:
Mass of CO₂ obtained = 53.0 grams
Mass of calcium carbonate heated = 1.31 grams
Now,
the molar mass of the calcium carbonate = 100.08 grams
The number of moles heated in the problem = Mass / Molar mass
= (1.31 grams) / (100.08 grams/moles)
= 0.013088 moles
now,
1 mol of calcium carbonate yields 1 mol of CO₂
thus,
0.013088 moles of calcium carbonate will yield = 0.013088 mol of CO₂
now,
Theoretical mass of 0.013088 moles of CO₂ will be
= Number of moles × Molar mass of CO₂
= 0.013088 × 44 = 0.5758 grams
Thus, the percent yield for this reaction = 
or
the percent yield for this reaction = 
or
the percent yield for this reaction = 92.04%