Answer:
The upper limit of a 95% confidence interval for the population mean would equal 83.805.
Step-by-step explanation:
The standard deviation is the square root of the variance. Since the variance is 25, the sample's standard deviation is 5.
We have the sample standard deviation, not the population, so we use the t-distribution to solve this question.
T interval:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 15 - 1 = 14
Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 0.95(). So we have T = 1.761
The margin of error is:
M = T*s = 1.761*5 = 8.805.
The upper end of the interval is the sample mean added to M. So it is 75 + 8.805 = 83.805.
The upper limit of a 95% confidence interval for the population mean would equal 83.805.
Answer:
grabbed
Step-by-step explanation:
just lose the is
Take the numbers times by the percent to start the Robles
Answer:
25 meters
Step-by-step explanation:
30 km/hr = (30 km/1 hr)*(1000 m/1 km)*(1 hr/60 min)*(1 min/60 sec)
30 km/hr = (30*1000*1*1)/(1*1*60*60) meters per second
30 km/hr = 8.3333333333 m/s (approximate)
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The speed or rate is r = 8.3333333333 meters per second approximately, and the time is t = 3 seconds, so,
distance = rate*time
d = r*t
d = 8.3333333333 * 3
d = 24.9999999999
Due to rounding error, the true answer should be d = 25. We can see this if we opted to use the fraction from of 8.3333... instead of the decimal representation which isn't a perfect exact measurement.
Answer:
Step-by-step explanation:
The position function for the free-falling object is , where t is measured in seconds and y is measured in meters. The velocity function is obtained by deriving it:
, where v is measured in meters per second.
Velocities at given times are, respectively: