Average atomic mass of an element is the sum of atomic mass of its isotopes multiplied by their respective percentage abundance.
There are four isotopes of element X:
1. 4.350 % with mass 49.94605 amu
2. 83.79% with mass 51.94051 amu
3. 9.5% with mass 52.94065 amu
4. 2.360% with mass 53.93888 amu
Thus, average atomic mass will be:
Or,
Therefore, average atomic mass of element X will be 51.99 amu (four significant figures)
Answer:
The molecules in 2,14 mol CO is 1, 29 x 10 ^ 24. See the explanation below, please.
Explanation:
We use the number of Avogadro:
1 mol----- 6, 02 x10 ^23 molecules
2,14 mol---- x =(2,14 mol x6, 02 x10 ^23 molecules )/ 1mol
x=1, 29 x 10 ^ 24 molecules
Answer:
7.5 × 10¹⁵ Hz
Explanation:
Given data
- Wavelength of the radio waves (λ): 40 nm = 40 × 10⁻⁹ m = 4.0 × 10⁻⁸ m
- Frequency of the radio waves (ν): ?
- Speed of light (c): 3.00 × 10⁸ m/s
We can determine the frequency of the radio waves using the following expression.
c = λ × ν
ν = c/λ
ν = (3.00 × 10⁸ m/s)/4.0 × 10⁻⁸ m
ν = 7.5 × 10¹⁵ s⁻¹ = 7.5 × 10¹⁵ Hz
Answer:
-A positively charged nucleus is surrounded by one
or more negatively charged electrons.