1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alisiya [41]
3 years ago
8

Aldehydes and ketones react reversibly with two equivalents of alcohol in the presence of an acid catalyst to give acetals. Alco

hols are poor nucleophiles, and so protonation of the carbonyl oxygen is used to make the carbonyl carbon a stronger electrophile. Addition of the first equivalent of alcohol gives a hemiacetal, a hydroxyether. Addition of the second equivalent of alcohol is accompanied by loss of water to yield the product acetal. Draw curved arrows to show the movement of electrons in this step of the mechanism.

Chemistry
1 answer:
kozerog [31]3 years ago
6 0

Answer:

Aldehyde and ketone both react with alcohols (2 equivalent) in the presence of acid catalyst to give acetals.

Explanation:

Alcohols are poor nucleophiles and so protonation of the carbonyl oxygen used to make the carbonyl carbon a stronger electrophile. Addition of the first equivalent of alcohols gives a hemiacetal,

Addition of the second equivalent of alcohol is accompanied by loss of one molecule water to yield the produce acetal.

You might be interested in
What is the capillary rise of ethanol in a glass tube with a 0.1 mm radius if the surface tension of ethanol is 0.032Jm2 and the
iragen [17]

Answer:

Explanation:

Expression for capillary rise is as follows

h = 2T / ρ g r where T is surface tension , ρ is density of liquid and r is radius of capillary tube.

T = .032 J m⁻²

ρ = .71 g / cm³

= 7100 kg / m³

r = .1 x 10⁻³ m = 10⁻⁴ m

h = 2 x .032 / (7100 x 9.8 x 10⁻⁴ )

h = .0092 m

= 9.2 mm .

5 0
2 years ago
How many moles of oxygen are needed to react with 100.0 grams of aluminum?
Tasya [4]

Answer:

2

Explanation:

8 0
2 years ago
Emperical formula of carbon dioxide
Stells [14]

CO2 is the emperical formula of carbon dioxide

6 0
2 years ago
Read 2 more answers
How many moles of sodium cyanide (NaCN) would be needed to produce 4.2 moles of sodium sulfate (Na2SO4)? H2SO4 + 2NaCN → 2HCN +
leonid [27]
The purpose of a chemical equation is to relate the amounts of reactants to the amounts of products based on the rate each is consumed. In this problem, one mole of sulfuric acid is consumed along with two moles of sodium cyanide to produce two moles of hydrocyanic acid and one mole of sodium sulfate. The relationship between sodium cyanide and sodium sulfate is 2:1, meaning that two moles of NaCN is required to produce one mole of sodium sulfate.

To produce 4.2 moles of sodium sulfate, two times this amount of NaCN is required. This means that you would need 8.4 moles of sodium cyanide.

Hope this helps!
4 0
3 years ago
Read 2 more answers
For an ideal gas, evaluate the volume occupied by 0.3 mole of gas.
Serhud [2]

Answer:

V=0.3×22.4=6.72 liters hope this helps

8 0
2 years ago
Other questions:
  • Which type of intermolecular attractive force operates between (part
    9·1 answer
  • Write reaction showing how each of the buffers would neutralize added naoh. hcho2 and nacho2
    10·1 answer
  • How do meteorologists make accurate weather predictions?
    9·1 answer
  • What is the molarity of 0.65 mol NaF dissolved in a total volume of 0.50 liters?
    8·1 answer
  • How would you create an ion with a -1 charge comparing number of electrons and protons
    7·1 answer
  • What physical property makes metal pot good for cooking
    7·1 answer
  • Which lists the elements in order from most conductive to least conductive?
    6·2 answers
  • Which is the largest in size? OA. A. a star O B. a planet O c. an asteroid D. a galaxy E. a supernova E.​
    14·1 answer
  • 7.95 x 1022<br> 6.02 x 1023
    9·1 answer
  • Mention the type of<br> Reaction common<br> to organic compound-
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!