Answer:
Explanation:
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This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:
Which accounts for an exothermic chemical reaction.
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Answer:
Paratroopers not hurt while landing because when they get to the ground, they keep their knees and feet together helping them to land properly.
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Answer:
The diagram shows oxygen, O₂, which consists of two atoms of oxygen in the stratosphere, which are the two beings holding hands, forming a couple being broken up by the intense ultraviolet radiation of the Sun, such that the couple closest to the Sun are the ones that were broken into two O, atoms.
After being broken, the two beings (oxygen atoms), become free to move as they please, making them able to move faster than when they were still a couple. However, due to the likeness for their fellow beings, each of the single O beings rushed to meet the other two still coupled O₂ beings, whereby one O being rushing to meet one O₂ couple each, to form O₃ which is a new group consisting of three beings holding hands known as Ozone
Note, that O stands for atomic oxygen gas
O₂ stands for oxygen gas
O₃ stands for ozone gas
Explanation:
Answer:
During complete oxidation of the fatty acid CH3(CH2)14COOH, eight molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven times.
Explanation:
In the β-oxidation of fatty acids, an acetyl-CoA molecule is removed from the fatty acid chain after every β-oxidation cycle that the fatty acid undergo, leaving behind a fatty acyl-CoA molecule shortened by two cabon atoms..
The removal of the acetyl-CoA molecule starts from the carboxyl end and shortens the fatty acid molecule by two carbon units. Successive β-oxidation cycles results in the complete oxidaton of the fatty acid molecle to acetyl -CoA molecules.
The compound CH3(CH2)14COOH, is a 16-carbon saturated fatty acid molecule known as palmitic acid.. It undergoes seven passes through the β-oxidation cycle to yield eight molecules of acetyl-CoA with each cycle yielding an acetyl-CoA molecule and a fatty acyl-CoA shortened by two carbon atoms. Finally, the seventh step yields two acetyl-CoA molecules.
Answer:
is equal to the number of protons in carbon (C).
