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sweet [91]
3 years ago
6

Consider the balanced chemical reaction when phosphorus and iodine react to produce phosphorus triodide: 2 P(s) + 3 I2(g) → 2 PI

3(g) If 58.6 g of I2(s) area reacted with excess P(s) to produce 0.147 mol of PI3(g), what is the percent yield of PI3(g)?
Chemistry
1 answer:
melamori03 [73]3 years ago
5 0

Answer:

Percent yield of PI3 = 95.4%

Explanation:

This is the reaction:

2P (s) + 3I2 (g) > 2PI3 (g)

Let's determine the moles of iodine that has reacted.

58.6 g / 253.8 g/mol = 0.231 mol

Ratio is 3:2. Let's make a rule of three to state the moles produced at 100 % yield reaction.

3 moles of I2 react to make 2 moles of PI3

0.231 moles of I2 would make (0.231 .2) / 3 = 0.154 moles of PI3

As we have produced 0.147 moles let's determine the percent yield.

(Yield produced / Theoretical yield) . 100 > (0.147 / 0.154) . 100 = 95.4%

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2. Which set of symbols represents isotopes of the same element?
MariettaO [177]

Answer:

so you can do the maths your self

Explanation:

isotopes are elements with he same proton number but difference in their neutron number

  • proton number is also known as the atomic number
  • mass number is the sum of the proton number and the neutron number
  • mass number = proton number + neutron number
7 0
3 years ago
Plan an investigation using solid and liquid water to show that thermal energy is not the same as temperature.
algol [13]

The investigation using solid and liquid water to show that thermal energy is not the same as temperature is:

  • Place a glass of water and a lake and both should be at the same temperature, find out if do they have the same amount of total thermal energy.

<h3>What is the response to the experiment above?</h3>

The response is No, because the lake is known to have a lot more particles than the glass of water and so they will not have the same  thermal energy.

Note that the temperature is seen as the an average and thermal energy is seen to be the total. A glass of water can be able to have the same temperature as what we call Lake Superior, but the lake has a lot of thermal energy due to the fact that the lake has a lot of water molecules.

So the investigation using solid and liquid water to show that thermal energy is not the same as temperature is Place a glass of water and a lake and both should be at the same temperature, find out if do they have the same amount of total thermal energy.

Learn more about thermal energy from

brainly.com/question/19666326

#SPJ1

4 0
1 year ago
I don’t get it plz help
d1i1m1o1n [39]
D=m/v. (Density equals mass over volume).
So in your case density = 4.2/6
Which equals 0.7
Your units will be grams over milliliters

So your answer is 0.7 g/ml
3 0
3 years ago
A 25.0 mLsample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5
matrenka [14]

Answer:

0.263M of CH₃COOH is the concentration of the solution.

Explanation:

The reaction of acetic acid (CH₃COOH) with NaOH is:

CH₃COOH + NaOH → CH₃COO⁻Na⁺ + H₂O

<em>1 mole of acetic acid reacts per mole of NaOH to produce sodium acetate and water.</em>

<em />

In the equivalence point, moles of acetic acid are equal to moles of NaOH and moles of NaOH are:

0.0375L × (0.175 moles / L) = 6.56x10⁻³ moles of NaOH = moles of CH₃COOH.

As the sample of acetic acid had a volume of 25.0mL = 0.025L:

6.56x10⁻³ moles of CH₃COOH / 0.0250L =

<em>0.263M of CH₃COOH is the concentration of the solution</em>

3 0
3 years ago
What is the mole fraction, X, of solute and the molality, m (or b), for an aqueous solution that is 15.0% NaOH by mass?
GalinKa [24]
Hello!

a) The mole fraction of solute of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams of water. We can calculate the number of moles of each one in the following way:

molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH \\ \\ moles H_2O=85 gH_2O* \frac{1 mol H_2O}{18 g H_2O}=4,7222 moles H_2O

To finish, we calculate the mole fraction by dividing the moles of NaOH between the total moles:

X_{NaOH}= \frac{moles NaOH}{total moles}= \frac{0,3750 moles NaOH}{0,3750 moles NaOH+4,7222 molesH_2O} =0,073

So, the mole fraction of NaOH is 0,073

b) The molality (moles NaOH/ kg of solvent) of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams (0,085 kg) of water. We can calculate the moles of NaOH in the following way:

molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH

Now, we apply the definition of molality to calculate the molality of the solution:

mNaOH= \frac{moles NaOH}{kg_{solvent}}=  \frac{0,3750 moles NaOH}{0,085 kg H_2O}=4,41 m

So, the molality of this solution is 4,41 m

Have a nice day!
4 0
3 years ago
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