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anzhelika [568]
3 years ago
6

Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wa

velength near 40nm.
Calculate the frequency of these radio waves.
Chemistry
1 answer:
NeTakaya3 years ago
5 0

Answer:

7.5 × 10¹⁵ Hz

Explanation:

Given data

  • Wavelength of the radio waves (λ): 40 nm = 40 × 10⁻⁹ m = 4.0 × 10⁻⁸ m
  • Frequency of the radio waves (ν): ?
  • Speed of light (c): 3.00 × 10⁸ m/s

We can determine the frequency of the radio waves using the following expression.

c = λ × ν

ν = c/λ

ν = (3.00 × 10⁸ m/s)/4.0 × 10⁻⁸ m

ν = 7.5 × 10¹⁵ s⁻¹ = 7.5 × 10¹⁵ Hz

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What is the volume, in liters, of 2.00 moles of hydrogen at STP?
Ber [7]
The volume of one mole of any gas at STP is 22.4 L. So, at STP, the volume of 2.00 moles of hydrogen gas would be (22.4 L/mol)(2 mol H2) = 44.8 L.
8 0
3 years ago
The pH at the equivalence point will be a. less than 7.00 b. equal to 7.00 Allohalineup of a sto quivalence point of a titration
True [87]

Answer: c. greater than 7.00

Explanation: The equivalence point of a titration is when all the base is consumed by the acid. When a strong base and a strong acid react, the medium is neutralized because is produced water and salt (which won't suffer hydrolysis). How water's pH is 7, in this type of titration the pH of the equivalence point will be at pH=7. But on titration of a weak acid with a strong base, the reaction of the equivalence point produces water and the conjugate base of the acid. Because the acid is weak, their conjugate base will be strong and will suffer hydrolysis, producing hydroxyl ions, elevating the pH of the water and making it greater than 7.

8 0
3 years ago
trial 2, 2.68 g/cm/3 trial 3, 2.84g/cm/3. aluminum has a density of 2.70g/cm/3 calcute the percent error for each trial.
serg [7]

Answer:

trial 2: 0.74

trial 3: 5.19

I think but the equation for sloving percent error is:

(true value - determined value)/true value * 100

Explanation:

6 0
3 years ago
The rate constant for a certain reaction is measured at two different temperatures:
Talja [164]

Answer: The activation energy Ea for this reaction is 22689.8 J/mol

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]

k_1 = rate constant at temperature T_1 = 2.3\times 10^8

k_2 = rate constant at temperature T_2 = 4.8\times 10^8

E_a= activation energy = ?

R= gas constant = 8.314 J/kmol

T_1 = temperature = 280.0^0C=(273+280)=553K

T_2 = temperature = 376.0^0C=(273+376)=649K

Putting in the values ::

ln \frac{4.8\times 10^8}{2.3\times 10^8} = \frac{-E_{a}}{8.314}[\frac{1}{649} - \frac{1}{553}]

E_a=22689.8J/mol

The activation energy Ea for this reaction is 22689.8 J/mol

3 0
3 years ago
How much time would it take for 5.2 x 10^5 atoms of fermium-253 (half-life 3 days) to decay to 6.5 x 104 atoms?
Jlenok [28]

Answer:

9 days, or 3 half-lives

Explanation:

5.2x10^5=520000

6.5x10^4=65000

65000/520000=1/8, or 3 half-lives

3x3=9 days

I'm not the greatest at Chem but this seems more like math than Chem :)

4 0
3 years ago
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