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Komok [63]
3 years ago
8

A weight of 20.0 N hangs motionless from a spring, with a spring constant of 65.0 N/m. How far is the spring stretched from its

original length?
0.130 m
0.308 m
0.769 m
3.25 m
Physics
2 answers:
Kay [80]3 years ago
8 0

Answer:

0.308 m

Explanation:

Force = spring constant * change in length

F = k * Δx

F = 20 N

k = 65 N/m

Δx = ? m

20 = 65 * Δx

20/65 = Δx

Δx = 0.308 m

Umnica [9.8K]3 years ago
6 0
Extension = force/spring constant.
extension = 20/65
extension = 0.308 m
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Answer:

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