- - The rate, according to physics, of doing work, is called "power"
Answer:
Δd = 7.22 10⁻² m
Explanation:
For this exercise we must use the dispersion relationship of a diffraction grating
d sin θ = m λ
let's use trigonometry
tan θ = y / L
how the angles are small
tant θ = sinθ /cos θ = sin θ
we substitute
sin θ = y / L
d y / L = m λ
y = m λ L / d
let's use direct ruler rule to find the distance between two slits
If there are 500 lines in 1 me, what distance is there between two lines
d = 2/500
d = 0.004 me = 4 10⁻⁶ m
diffraction gratings are built so that most of the energy is in the first order of diffraction m = 1
let's calculate for each wavelength
λ = 656 nm = 656 10⁻⁹ m
d₁ = 1 656 10⁻⁹ 1.7 / 4 10⁻⁶
d₁ = 2.788 10⁻¹ m
λ = 486 nm = 486 10⁻⁹ m
d₂ = 1 486 10⁻⁹ 1.7 / 4 10⁻⁶
d₂ = 2.066 10⁻¹ m
the distance between the two lines is
Δd = d1 -d2
Δd = (2,788 - 2,066) 10⁻¹
Δd = 7.22 10⁻² m
Answer: 3.76 mm
Explanation: The formulae that defines the position of a nth fringe from the center of a double slit interference experiment is given below as
y =R×mλ/d
Where y = distance between the nth fringe and the center
R = distance between slits and screen = 1.71 m
m = position of fringe = 1
d = distance between slits = 0.254 mm = 0.000254m
λ = wavelength of light = 559 nm = 559×10^-9m
By substituting parameters, we have that
y = 1.71×1×559×10^-9/0.000254
y = 0.00000095589 / 0.000254
y = 0.00376m = 3.76 mm
Answer:
small car since they weigh less than a bus
Explanation:
There would be 6 electrons placed on the third energy level.
