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BlackZzzverrR [31]
3 years ago
14

A charge of 70 A ·h (ampere-hours) moves through a poten- difference of 25 V. What are (a) the charge in coulombs and(b) the mag

nitude of the change in the potential energy of the charge?
Physics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer

Given,

Charge, q = 70 A.h

Potential difference, V = 25 V

a) Charge, q = ?

we know that

  q= I t

    = 70 A.h

    = 70 x 60 x 60 A.s

    = 252,000 C

b) Potential energy of the charge

      U = q V

      U =  252,000 x 25

      U = 6,300,000 J

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An advanced computer sends information to its various parts via infrared light pulses traveling through silicon fibers (n = 3.50
sasho [114]

Answer:

d = 6.43 cm

Explanation:

Given:

- Speed resistance coefficient in silicon n = 3.50

- Memory takes processing time t_p = 0.50 ns

- Information is to be obtained within T = 2.0 ns

Find:

- What is the maximum distance the memory unit can be from the central processing unit?

Solution:

- The amount of time taken for information pulse to travel to memory unit:

                            t_m = T - t_p

                            t_m = 2.0 - 0.5 = 1.5 ns

- We will use a basic relationship for distance traveled with respect to speed of light and time:

                           d = V*t_m

- Where speed of light in silicon medium is given by:

                           V = c / n

- Hence,              d = c*t_m / n

-Evaluate:           d = 3*10^8*1.5*10^-9 / 3.50

                           d = 0.129 m 12.9 cm

- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm

8 0
3 years ago
The volume of water in the Pacific Ocean is about 7.0 × 10 8 km 3 . The density of seawater is about 1030 kg/m3. (a) Determine t
Novay_Z [31]

To solve the problem it is necessary to consider the concepts related to Potential Energy and Kinetic Energy.

Potential Energy because of a planet would be given by the equation,

PE=\frac{GMm}{r}

Where,

G = Gravitational Universal Constant

M = Mass of Ocean

M = Mass of Moon

r = Radius

From the data given we can calculate the mass of the ocean water through the relationship of density and volume, then,

m = \rho V

m = (1030Kg/m^3)(7*10^8m^3)

m = 7.210*10^{11}Kg

It is necessary to define the two radii, when the ocean is far from the moon and when it is facing.

When it is far away, it will be the total diameter from the center of the earth to the center of the moon.

r_1 = 3.84*10^8 + 6.4*10^6 = 3.904*10^8m

When it's near, it will be the distance from the center of the earth to the center of the moon minus the radius,

r_2 = 3.84*10^8-6.4*10^6 - 3.776*10^8m

PART A) Potential energy when the ocean is at its furthest point to the moon,

PE_1 = \frac{GMm}{r_1}

PE_1 = \frac{(6.61*10^{-11})*(7.21*10^{11})*(7.35*10^{22})}{3.904*10^8}

PE_1 = 9.05*10^{15}J

PART B) Potential energy when the ocean is at its closest point to the moon

PE_2 = \frac{GMm}{r_2}

PE_2 = \frac{(6.61*10^{-11})*(7.21*10^{11})*(7.35*10^{22})}{3.776*10^8}

PE_2 = 9.361*10^{15}J

PART C) The maximum speed. This can be calculated through the conservation of energy, where,

\Delta KE = \Delta PE

\frac{1}{2}mv^2 = PE_2-PE_1

v=\sqrt{2(PE_2-PE_1)/m}

v = \sqrt{\frac{2*(9.361*10^{15}-9.05*10^{15})}{7.210*10^{11}}}

v = 29.4m/s

8 0
3 years ago
When there is a large unbalanced charge in a conductor, positive charges will move through the conductor when another
GuDViN [60]
This is true; it needs to balance it’s charge. However, it could also be negative charges as well.
7 0
2 years ago
A 25N force is applied to a bar that can pivot around its end. The force is r=0.75 m away from the end of an angle at 0= 45. wha
andrew-mc [135]

Answer:

The answer is B. I had a question like this last week in my physics practice exam. dont have alot of time so I cant explain right now

Explanation:

8 0
2 years ago
Please help me
-Dominant- [34]

Answer:

D) Aerobic respiration is very efficient and produces a large amount of energy, while anaerobic respiration is not very efficient and produces a small amount of energy.

Explanation:

Anaerobic respiration, which uses glucose and no oxygen, produces less energy compared to aerobic respiration.

8 0
3 years ago
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