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BlackZzzverrR [31]
2 years ago
14

A charge of 70 A ·h (ampere-hours) moves through a poten- difference of 25 V. What are (a) the charge in coulombs and(b) the mag

nitude of the change in the potential energy of the charge?
Physics
1 answer:
kenny6666 [7]2 years ago
3 0

Answer

Given,

Charge, q = 70 A.h

Potential difference, V = 25 V

a) Charge, q = ?

we know that

  q= I t

    = 70 A.h

    = 70 x 60 x 60 A.s

    = 252,000 C

b) Potential energy of the charge

      U = q V

      U =  252,000 x 25

      U = 6,300,000 J

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Take into account that density and relative density are given by:

\begin{gathered} \text{density}=\text{ mass/volume} \\ \text{relative density = density/density of water} \end{gathered}

Take into account that the volume associated to each of the given sustances in the table is determined by the Level Difference (because it is the change in the volume of the water of the recipient in which the substance is immersed).

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\begin{gathered} 53.2g\cdot\frac{1kg}{1000g}=0.0532kg \\ 6ml\cdot\frac{1m^3}{1000000ml}=0.000006m^3 \\ \text{density}=\frac{0.0532kg}{0.000006m^3}\approx8866.67\frac{kg}{m^3} \\ \text{relative density=}\frac{(\frac{8866.66kg}{m^3})}{(1000\frac{kg}{m^3})}\approx8.87 \end{gathered}

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\begin{gathered} 57.4g=0.0574kg \\ 6ml=0.000006m^3 \\ \text{density}=\frac{0.0574kg}{0.000006m^3}\approx9566.67\frac{kg}{m^3} \\ \text{relative density=}\frac{\frac{9566.67kg}{m^3}}{1000kg}=9.57 \end{gathered}

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1 year ago
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