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Sati [7]
3 years ago
9

N Rutherford's gold foil experiment the alpha particles pass through which part of the atom?

Physics
1 answer:
OleMash [197]3 years ago
3 0
It passes through C the Electron Cloud
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How can a protein outside the cell cause events to happen inside the cell?
jeka57 [31]

Answer:

Explained

Explanation:

The proteins(sometimes are called celluar ligands) outside the cell can bind to a receptor protein( generally found on the cell membranes) on the cell surface, causing it( receptor protein) to change the shape and sending a signal inside the cell.

8 0
3 years ago
When seen from an airplane, a rainbow sometimes forms a complete circle. When this happens, the plane's shadow is a. in the cent
ValentinkaMS [17]

Answer:

A. in the center of the rainbow

Explanation:

A rainbow is always seen half circle

For one to see the full circle of the rain bow, it will appear that the shadow of the object will be found in the centre of the rain bow.

6 0
4 years ago
A cannonball is shot horizontally off a
inn [45]

Answer:it's 132.2m

Explanation:

Hello !

Because first recall parabolic peak height equation and

given that v=47.4m/s , h=10.5m

  • v²sin²(θ⁰)=2ℎ₀
  • (47.4)²²(θ⁰)=2(9.81)(10.5)
  • θ=17.63

secondly recall parabolic total distance equation

  • d₀=²(2θ⁰)/g
  • d₀=(47.4)²(2(17.63)⁰)/9.81
  • d₀=132.2m
5 0
2 years ago
Does light need a medium to transfer energy
horrorfan [7]

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space. ... This proved that radio waves were a form of light!

8 0
3 years ago
Read 2 more answers
An inflatable raft (unoccupied) floats down a river at an approximately constant speed of 5.2 m/s. A child on a bridge, 63 m abo
Fittoniya [83]

Answer:18.64 m

Explanation:

Given

speed of raft=5.2 m/s

height of bridge=63 m

let the distance between the raft and bridge be x

t = time taken by stone to reach at bottom

x=5.2\times t

h=ut+\frac{at^2}{2}

63=0+\frac{9.8t^2}{2}

t^2=12.857

t=3.58 s

x=5.2\times 3.58=18.64 m

4 0
3 years ago
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