The subatomic particle that gives off visible light is electrons
PV=nRT n=PV/RT
R=.0821 atm x L
Mol x K
T=318K
P=.55atm
V=37.4L
n= (.55atm) (37.4L) /
.0821atm x L (318k)
mol x K
n= .79 mol of sulfur dioxide
Answer:
2.19L
Explanation:
Information from the question include:
V1 (initial volume) = 2.3L
P1 (initial pressure) = 725mmHg
P2 (final pressure) = 760mmHg
V2 (final volume) =?
With the Boyle's law equation P1V1 = P2V2, the final volume can easily be obtain as follow:
P1V1 = P2V2
725 x 2.3 = 760 x V2
Divide both side by 760
V2 = (725 x 2.3)/760
V2 = 2.19L
Therefore, the new volume of the gas at standard pressure is 2.19L
Answer:
32.76mole of P
Explanation:
The reaction expression is given as;
P₄O₁₀ → 4P + 5O₂
Given parameters:
Number of moles of P₄O₁₀ = 8.19mol
Unknown:
Number of moles of P produced = ?
Solution:
From the balanced reaction expression;
1 mole of P₄O₁₀ will produce 4 mole of P
8.19mole of P₄O₁₀ will therefore produce 4 x 8.19 = 32.76mole of P
