Answer:
a. 7.24m
b. 5.15M
c. 53.4mL of the solution would contain this amount of ethanol.
Explanation:
Molality, m, is defined as the moles of solute (ethanol, in this case) per kg of solvent.
Molarity, M, are the moles of solute per kg of solvent
To solve this question we need to find the moles of solute in 100g of solution and the volume using its density as follows:
a. <em>Moles ethanol -Molar mass: 46.07g/mol-:</em>
25g ethanol * (1mol/46.07g) = <em>0.54265 moles ethanol</em>
<em>kg solvent:</em>
100g solution - 25g solute = 75g solvent * (1kg / 1000g) = 0.075kg
<em>Molality:</em>
0.54265 moles ethanol / 0.075kg = 7.24m
b. <em>Liters solution:</em>
100g solution * (1mL / 0.950g) = 105.3mL * (1L / 1000mL) = <em>0.1053L</em>
<em>Molarity:</em>
0.54265 moles ethanol / 0.1053L = 5.15M
c. 0.275 moles ethanol * (1L / 5.15moles Ethanol) = 0.0534L =
53.4mL of the solution would contain this amount of ethanol
