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tamaranim1 [39]
3 years ago
12

What property of water is primary for living organisms? (SC.6.E.7.4) *

Chemistry
1 answer:
katrin [286]3 years ago
8 0

Answer:

It is liquid at most temperatures on Earth.

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Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

7 0
3 years ago
If 600.0 ml of air at 20.0 c is heated to 60.0L , what will be its volume
Deffense [45]
P1v1/t1 = p2t2/t2

p is constant
v1=600, t1 =20c=293K
v2=?, t2=60c=333K
temperature must be in Kelvin

do the math
5 0
3 years ago
What is the engine piston displacement in liters of an engine who’s displacement is listed as 430 in.²
sergeinik [125]

For an engine whose displacement is listed as 430 in.², the engine piston displacement in liters is mathematically given as

PD= 7.37 L  

<h3>What is the engine piston displacement in liters of an engine whose displacement is listed as 430 in.²?</h3>

Generally, the equation for the dimensional analysis method,\, we convert in to L is mathematically given as

l*(v/l)*l/v

Therefore,  piston displacement

PD=(450 in3) . (1 dm3 / 61.024 in3) . (1 L / 1 dm3)

PD= 7.37 L  

In conclusion, piston displacement

PD= 7.37 L  

Read more about volume

brainly.com/question/1578538

#SPJ1

6 0
2 years ago
How many grams of CO₂ can be produced from the combustion of 2.76 moles of butane according to this equation: 2 C₄H₁₀(g) + 13 O₂
Vilka [71]

Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

Combustion reaction:

2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)

If we only have the amount of butane, we assume the oxygen is the excess reagent.

Ratio is 2:8. Let's make a rule of three:

2 moles of butane can produce 8 moles of dioxide

Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂

We convert the moles to mass → 11.04 mol . 44g / 1 mol = 485.76 g

5 0
3 years ago
In the reaction 2CO (g) + O2 (g) 2CO2 (g), how many moles of oxygen gas are needed to react with 24 moles of carbon monoxide
Anuta_ua [19.1K]

12 moles of oxygen gas are needed to react with 24 moles of carbon monoxide.

<u>Explanation:</u>

The molar ratio of carbon monoxide to oxygen 2:1

Which means 2 moles of carbon monoxide is reacting with 1 mole of oxygen.

to produce 2 moles of carbon dioxide.

Therefore, from the molar ratio, we get that 12 moles of oxygen are required to react with 24 moles 0f carbon monoxide.

Molar ratio:

The molar ratio gives the moles of product that are formed from a certain amount of reactant, and also the number of moles of a reactant needed to react with another reactant.

4 0
3 years ago
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