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ch4aika [34]
2 years ago
9

Factors that cause pain and illness in household work

Chemistry
1 answer:
Trava [24]2 years ago
7 0

Answer:

crucial premise in the study of illness behavior is that illness, as well as the illness experience, are shaped by psychological, social, and cultural factors irrespective of the genetic, physiological, or other biological bases of disease. Hence, as used here, illness and disease are distinct.

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At 35.0°c and 3.00 atm pressure, a gas has a volume of 1.40 l. what pressure does the gas have at 0.00°c and a volume of 0.950 l
Leona [35]

Answer : The pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 3 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 1.40 L

V_2 = final volume of gas = 0.950 L

T_1 = initial temperature of gas = 35^oC=273+35=308K

T_2 = final temperature of gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{3atm\times 1.40L}{308K}=\frac{P_2\times 0.950L}{273K}

P_2=3.918atm

Therefore, the pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

4 0
3 years ago
Read 2 more answers
The diagram below shows changes to the nucleus of an atom.
anzhelika [568]

Answer:

maybe 1 or 3 im not sure

Explanation:

i didn't study it yet sorry for not helping but try asking someone else

8 0
2 years ago
Read 2 more answers
B. MgF2<br> Name the compound
algol [13]

Answer:

Magnesium Difluoride

Explanation:

Mg = magnesium

F = fluoride

F2 = difluoride (prefix "di" indicates 2)

5 0
3 years ago
Consider the following first order decomposition reaction with a half-life of 65 seconds at a given temperature:
katrin [286]

Answer:

130

Explanation:

This is because that 3atm of N2O4 is used up for the 6atm of NO2, so 1 atm N2O4 is left. Resulting in In(1/4).

6 0
2 years ago
A 10.0 mL sample of HNO3 was exactly neutralized by 13.5 mL of 1.0 M KOH. What is the molarity of the HNO3? Use the titrations f
Kruka [31]

Answer: Thus molarity of HNO_3 is 1.35 M

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=?M\\V_1=10.0mL\\n_2=1\\M_2=1.0M\\V_2=13.5mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 1.0\times 13.5\\\\M_1=1.35M

Thus molarity of HNO_3 is 1.35 M

7 0
3 years ago
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