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ch4aika [34]
2 years ago
9

Factors that cause pain and illness in household work

Chemistry
1 answer:
Trava [24]2 years ago
7 0

Answer:

crucial premise in the study of illness behavior is that illness, as well as the illness experience, are shaped by psychological, social, and cultural factors irrespective of the genetic, physiological, or other biological bases of disease. Hence, as used here, illness and disease are distinct.

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2. Barium compounds are chemically very similar to strontium compounds. Water-soluble
harina [27]

The ability of sodium sulfate to act as an antidote to barium chloride poisoning is because displaces barium in barium chloride to form sodium chloride and insoluble harmless barium sulfate.

<h3>Why is a solution of sodium sulfate used as an antidote?</h3>

The ability of sodium sulfate to act as an antidote to barium chloride poisoning is because of the reactivity of sodium.

Sodium is a more reactive metal than barium, so it displaces barium in barium chloride to form sodium chloride and insoluble harmless barium sulfate.

The equation of the reaction is given below:

  • BaCl2 + Na2SO4 ----> BaSO4 + NaCl

Therefore, the ability of sodium sulfate to act as an antidote to barium chloride poisoning is because displaces barium in barium chloride to form sodium chloride and insoluble harmless barium sulfate.

Learn more about about reactivity of metals at: brainly.com/question/24866635

6 0
2 years ago
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Conduction is the transfer of energy by the movement of currents. ture or false <br>​
Mandarinka [93]

conduction is the transfer of energy by the movement of currents(it is true)

8 0
3 years ago
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. 125g of water has an initial temperature of 25.6°C, and is heated by 50.0g of a metal
Eduardwww [97]

Answer : The specific heat of the metal is, 0.451J/g^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of metal = 50.0 g

m_2 = mass of water  = 125 g

T_f = final temperature of mixture = 29.3^oC

T_1 = initial temperature of metal = 115.0^oC

T_2 = initial temperature of water = 25.6^oC

Now put all the given values in the above formula, we get

(50.0g)\times c_1\times (29.3-115.0)^oC=-[(125g)\times 4.18J/g^oC\times (29.3-25.6)^oC]

c_1=0.451J/g^oC

Therefore, the specific heat of the metal is, 0.451J/g^oC

4 0
3 years ago
How much heat is required to take a 150 g sample of water from 10.0 ℃ to 95.0 ℃? cs,water = 4.184 J/g*℃
oee [108]

Answer don't know at all but i will find out by tomorrow

Explanation: sorry

6 0
3 years ago
Which of the following best explains the Law of Conservation of Mass?
Katena32 [7]

Answer:

A

Explanation:

When a reaction happens some of the reactants mass is released as energy so the mass of the product would be less

3 0
3 years ago
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