Answer:
8 * (7 + 4)
See process below
Step-by-step explanation:
We start by writing each number in PRIME factor form:
56 = 2 * 2 * 2 * 7
32 = 2 * 2 * 2 * 2 * 2
Notice that the factors that are common to BOTH numbers are 2 * 2 * 2 (the product of three factors of 2).Therefore we see that the greatest common factor for the given numbers is : 2 * 2 * 2 = 8
Using this, we can write the two numbers as the product of this common factor (8) times the factors that are left on each:
56 = 8 * 7
32 = 8 * 2 * 2 = 8 * 4
We can then use distributive property to "extract" that common factor (8) from the given addition as shown below:
56 + 32
8 * 7 + 8 * 4
8 * (7 + 4)
8 * (11)
88
3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191 those are some prime numbers :)
Option C
Math teacher would need to buy 130 prizes
<em><u>Solution:</u></em>
Given that,
Math teacher currently has 109 students and the box has 88 prizes in it
The math teacher likes to keep at least twice as many prizes in the box as she has students
So, she wants the number of prizes to be twice the number of students
Therefore,
number of prizes = 2 x 109 students
number of prizes = 2 x 109 = 218 prizes
The box has 88 prizes in it
Therefore, number of prizes she would need to buy is:
⇒ 218 - 88 = 130
Thus she would need to buy 130 prizes
Answer:
I'm guessing it's C because it's the only one that looks right
