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ser-zykov [4K]
3 years ago
5

Cuál es la suma de los primeros 30 términos de la sucesión 1,2,3,4​

Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

465

Step-by-step explanation:

1 + 2 + 3 + ... + n = n(n + 1)/2

1 + 2 + 3 + ... + 30 = 30(31)/2 = 465

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Y equals the quotient of the quantity x squared plus 4 times x and the quantity x cubed minus 5.
koban [17]

Given:

Consider the completer question is "Find the derivative \dfrac{dy}{dx} for y=\dfrac{x^2-4x}{x^3-5}."

To find:

The derivative \dfrac{dy}{dx}.

Solution:

Chain rule: \dfrac{d}{dx}f(g(x))=f'(g(x))\cdot g'(x)

Quotient rule: \dfrac{d}{dx}\dfrac{f(x)}{g(x)}=\dfrac{g(x)f'(x)-f(x)g'(x)}{[g(x)]^2}

We have,

y=\dfrac{x^2-4x}{x^3-5}

Differentiate with respect to x.

\dfrac{dy}{dx}=\dfrac{d}{dx}\left(\dfrac{x^2-4x}{x^3-5}\right)

Using chain rule and quotient rule, we get

\dfrac{dy}{dx}=\dfrac{(x^3-5)\dfrac{d}{dx}(x^2-4x)-(x^2-4x)\dfrac{d}{dx}(x^3-5)}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{(x^3-5)(2x-4)-(x^2-4x)(3x^2)}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{2x^4-4x^3-10x+20-3x^4+12x^3}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}

Therefore, the required answer is \dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}.

4 0
2 years ago
What is the value of xxx in the figure shown below?
iVinArrow [24]

Answer:

the value of x is 31 degrees

7 0
2 years ago
Need Help ASAP please
liberstina [14]
Try asking googleee cuz that’s hard siisss
3 0
2 years ago
At about 9:00 PM every night, flights from Chicago, Miami, and Denver arrive at the local airport in a random order. What is the
Lelu [443]

Answer:

The answer is 1/3

Step-by-step explanation:

Since there are 3 planes that arrive in a random order, there is a 1 in 3 chance that the plane from Chicago will arrive first. Hope this helps!

3 0
3 years ago
If the theater has 180 seats in 20 rows, then how many seats are there in 4 rows?
UkoKoshka [18]

Answer:

The sum is 10(16 + 54) =700

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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