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2 years ago

F(t) 2t-3 F(7)=? What does f(7) equal?

Mathematics

2 answers:

Usimov [2.4K]2 years ago

7 0

Answer:

f(7)=2/7t+-3/7

Step-by-step explanation:

you just have to plug 7 in and put an = sign which makes F(7)=2t-3 then solve

myrzilka [38]2 years ago

6 0

Answer:

F(7) = 11

Step-by-step explanation:

F(7) = 2(7) -3

= 14 - 3

= 11

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Would you rather save 25% off or save one third?

Trava [24]

Answer:

One-third

Step-by-step explanation:

One-third (which is about 33.3%) is greater than 25%

7 0

2 years ago

Read 2 more answers

Joe measured the diameter of a tennis ball correct to the nearest millimetre. The upper bound of his measurement was 6.75 centim

Mandarinka [93]

The lower bound of the measurement is 65.5 millimetres.

A centimetre equals 10 millimetres, a measure is expressed by the <em>measured</em> magnitude plus uncertainty, the latter one represents the grade of precision of the measure instrument. That is to say:

$y = x + \epsilon$ (1)

Where:

$x$ - Measured magnitude, in millimeters.
$y$ - Possible magnitude, in millimeters.
$\epsilon$ - Uncertainty, in millimeters.

If we know that $y = 67.5\,mm$ and $\epsilon = 1\,mm$ , then the lower bound of the measurement is:

$y = 67.5\,mm - 2\cdot (1\,mm)$

$y = 65.5\,mm$

The lower bound of the measurement is 65.5 millimeters.

We kindly invite to check this question on measurements: brainly.com/question/4205362

4 0

2 years ago

Find all the complex roots. Write the answer in exponential form.

dezoksy [38]

We have to calculate the fourth roots of this complex number:

$z=9+9\sqrt[]{3}i$

We start by writing this number in exponential form:

$\begin{gathered} r=\sqrt[]{9^2+(9\sqrt[]{3})^2} \\ r=\sqrt[]{81+81\cdot3} \\ r=\sqrt[]{81+243} \\ r=\sqrt[]{324} \\ r=18 \end{gathered}$ $\theta=\arctan (\frac{9\sqrt[]{3}}{9})=\arctan (\sqrt[]{3})=\frac{\pi}{3}$

Then, the exponential form is:

$z=18e^{\frac{\pi}{3}i}$

The formula for the roots of a complex number can be written (in polar form) as:

$z^{\frac{1}{n}}=r^{\frac{1}{n}}\cdot\lbrack\cos (\frac{\theta+2\pi k}{n})+i\cdot\sin (\frac{\theta+2\pi k}{n})\rbrack\text{ for }k=0,1,\ldots,n-1$

Then, for a fourth root, we will have n = 4 and k = 0, 1, 2 and 3.

To simplify the calculations, we start by calculating the fourth root of r:

$r^{\frac{1}{4}}=18^{\frac{1}{4}}=\sqrt[4]{18}$

<em>NOTE: It can not be simplified anymore, so we will leave it like this.</em>

Then, we calculate the arguments of the trigonometric functions:

$\frac{\theta+2\pi k}{n}=\frac{\frac{\pi}{2}+2\pi k}{4}=\frac{\pi}{8}+\frac{\pi}{2}k=\pi(\frac{1}{8}+\frac{k}{2})$

We can now calculate for each value of k:

$\begin{gathered} k=0\colon \\ z_0=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{0}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{0}{2}))) \\ z_0=\sqrt[4]{18}\cdot(\cos (\frac{\pi}{8})+i\cdot\sin (\frac{\pi}{8}) \\ z_0=\sqrt[4]{18}\cdot e^{i\frac{\pi}{8}} \end{gathered}$ $\begin{gathered} k=1\colon \\ z_1=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{1}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{1}{2}))) \\ z_1=\sqrt[4]{18}\cdot(\cos (\frac{5\pi}{8})+i\cdot\sin (\frac{5\pi}{8})) \\ z_1=\sqrt[4]{18}e^{i\frac{5\pi}{8}} \end{gathered}$ $\begin{gathered} k=2\colon \\ z_2=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{2}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{2}{2}))) \\ z_2=\sqrt[4]{18}\cdot(\cos (\frac{9\pi}{8})+i\cdot\sin (\frac{9\pi}{8})) \\ z_2=\sqrt[4]{18}e^{i\frac{9\pi}{8}} \end{gathered}$ $\begin{gathered} k=3\colon \\ z_3=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{3}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{3}{2}))) \\ z_3=\sqrt[4]{18}\cdot(\cos (\frac{13\pi}{8})+i\cdot\sin (\frac{13\pi}{8})) \\ z_3=\sqrt[4]{18}e^{i\frac{13\pi}{8}} \end{gathered}$

Answer:

The four roots in exponential form are

z0 = 18^(1/4)*e^(i*π/8)

z1 = 18^(1/4)*e^(i*5π/8)

z2 = 18^(1/4)*e^(i*9π/8)

z3 = 18^(1/4)*e^(i*13π/8)

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10 months ago

Help me do the rest somebody pleaseeeeee

Len [333]

Answer:

so it's like the push factors are the ones that makes you want to leave that place cuz of negative life style are pull factors are like the positive things about that place that it makes you want to stay there.. I have posted the answers in the other one check it

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2 years ago

Z + 6 over 3 = 2z over 4

Black_prince [1.1K]

$\frac{z + 6}{3}$ = $\frac{2z}{4}$ Multiply both sides by 3
z + 6 = $\frac{(3)2z}{4}$ Multiply both sides by 4
(4)z + 6 = (3)2z Simplify
4z + 24 = 6z Subtract 4z from both sides
24 = 2z Divide both sides by 2
12 = z Flip the sides to make it easier to read
z = 12

7 0

2 years ago