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3 years ago

4.5 tons → lbs 4.5 tons equals how many pounds

Chemistry

2 answers:

galben [10]3 years ago

8 0

Answer: 9000 lbs.

Explanation: 4.5 tons = 9000 pounds.

maks197457 [2]3 years ago

4 0

Answer:

9000 pounds

Explanation:

9000 pounds

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What type of bond forms between two oxygen atoms?

uranmaximum [27]

Covalent bond is the correct answer

7 0

3 years ago

Methane is a gas at room temperature and pressure. Explain why this is the case.

Sveta_85 [38]

Answer:

hope it helps ❤

Explanation:

Methane only has london dispersion forces since it is nonpolar. London dispersion force is the weakest intermolecular force, so the forces between its molecules will be weak. This leads to a low boiling point that is lower than room temperature, which makes it a gas at room temperature.

4 0

3 years ago

Read 2 more answers

Seven carbon chain with CH3 attached to second and third carbon

Nikitich [7]

Answer:

2,3-dimethylheptane.

CH₃ - CH - CH-CH₂-CH₂-CH₂-CH₂

| |

CH₃ CH₃

Explanation:

Hello there!

In this case, according to the given instructions, it is possible to draw the organic chemical structure by connecting seven carbon atoms along the parent chain with two methyl substituents at the second and third carbon atoms; thus, the resulting structure is:

CH₃ - CH - CH-CH₂-CH₂-CH₂-CH₂

| |

CH₃ CH₃

Furthermore, the name would be 2,3-dimethylheptane according to the IUPAC rules for nomenclature.

Best regards!

6 0

3 years ago

Calculate the number of pounds of CO2 released into the atmosphere when a 22.0 gallon tank of gasoline is burned in an automobil

IrinaK [193]

Answer:

391.28771 pounds of carbon-dioxide released into the atmosphere.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasolin be M

$d=\frac{M}{V}$

M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Assume that gasoline is primarily octane (given)

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08 g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide released into the atmosphe

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3 years ago

10.0 g of calcium carbonate is treated with 10.0 g of HCl and,

Marysya12 [62]

Answer:

3.5

Explanation:

8 0

3 years ago