Explanation:
The given data is as follows.
= 10 mM = 
M
= 750 ml, 
= 5 ml
= ?
Therefore, calculate the molarity of given NaCl stock as follows.
= 1.5 M
Thus, we can conclude that molarity of given NaCl stock is 1.5 M.
Answer:
193.5-195 °C.
Explanation:
Hello!
In this case, since the mixture is 50:50, we can infer that an average may be used to compute the required range; thus, we first compute the the inner limit by using 135 °C and 252 °C:
And the upper limit:
Thus, the average melting point would be around 193.5-195 °C.
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The Nucleus I think Fam.................... <span />
Answer:
what does that supposed to mean?
Change in Gibb's free energy of system (ΔG) = ΔH - TΔS.........(Eq. 1)
Now, if magnitude of ΔG <0, then reaction is spontaneous.
if magnitude of ΔG > 0, then reaction is non-spontaneous.
At equilibrium, ΔG = 0
When at boiling point, liquid state is in equilibrium with vapour state. Hence, it present case ΔG = 0
∴ Eq 1 becomes, ΔH = TΔS
here, ΔH = 58.2 kj/mol (Given),
∴ At T = 83.4 oC = 356.4 K, ΔS = 0.1633 kj/mol.K
