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ozzi
2 years ago
12

Seven carbon chain with CH3 attached to second and third carbon

Chemistry
1 answer:
Nikitich [7]2 years ago
6 0

Answer:

2,3-dimethylheptane.

CH₃ - CH - CH-CH₂-CH₂-CH₂-CH₂

           |        |

       CH₃    CH₃

Explanation:

Hello there!

In this case, according to the given instructions, it is possible to draw the organic chemical structure by connecting seven carbon atoms along the parent chain with two methyl substituents at the second and third carbon atoms; thus, the resulting structure is:

CH₃ - CH - CH-CH₂-CH₂-CH₂-CH₂

           |        |

       CH₃    CH₃

Furthermore, the name would be 2,3-dimethylheptane according to the IUPAC rules for nomenclature.

Best regards!

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Calculate the volume of 1M NaOH required to neutralize 200 cc of 2M HCI. What mass of sodium
Nezavi [6.7K]

NaOH+HCl-> NaCl+H2O

1 mole of NaOH

1 mole of HCl.

To calculate volume of NaOH

CaVa/CbVb= Na/Nb

Where Ca=2M

Cb=1M

Va=200cm³

Vb=xcm³

Substitute into the equation.

2×200/1×Vb=1/1

400/Vb=1/1

Cross multiply

Vb×1=400×1

Vb=400cm³

To calculate the mass of sodium chloride, NaCl from the neutralization rxn.

Mole of NaCl=1

Molar mass of NaCl= 23+35.5=58.5

Mass=xgrammes.

Mass of NaCl=Number of moles × Molar mass.

Substitute

Mass of NaCl= 1×58.5

=58.5g

This is what I could come up with.

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3 years ago
Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at
kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

r = \frac{1 }{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

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Squaring both sides, we get

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Solve for <em>M</em>₂:

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....................................................................................................................................

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