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2 years ago

Carbon dioxide in the atmosphere can be reduced by _.*

Chemistry

2 answers:

Dima020 [189]2 years ago

7 0

Answer:

Less driving by yourself and more carpooling to reduce the amount of cars releasing Carbon dioxide into the air.

Explanation:

pychu [463]2 years ago

6 0

Answer:

As the use of plants as carbon sinks can be undone by events such as wildfires, the long-term reliability of these approaches has been questioned. Carbon dioxide that has been removed from the atmosphere can also be stored in the Earth's crust by injecting it into the subsurface, or in the form of insoluble carbonate salts (mineral sequestration).

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Explanation:

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The surface of the earth is divided into more than 50 large plates

Romashka-Z-Leto [24]

Major Plates

Africa Plate
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Indo-Australian Plate
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Eurasian Plate
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Minor Plates
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5 0

3 years ago

Suppose you were preparing 1.0 L of a bleaching solution in a volumetric flask, and it calls for 0.21 mol of NaOCl. If all you h

yulyashka [42]

Answer:

0.256 L

Explanation:

We should use the following formula:

concentration (1) × volume (1) = concentration (2) × volume (2)

concentration (1) = 0.82 M NaOCl

volume (1) = ?

concentration (2) = 0.21 M NaOCl

volume (2) = 1 L

volume (1) = [concentration (2) × volume (2)] / concentration (1)

volume (1) = [0.21 / 1] / 0.82 = 0.256 L

3 0

3 years ago

Read 2 more answers

You water three sunflower plants with salt water. Each plant receives a different concentration of salt solutions. A fourth plan

quester [9]

Answer:

Please please please mark me brainlest!

Explanation:

IV: salt solution

DV: Hight of plants

Control: the fourth plant

Independent Variable: what it's watered with (regular water or salt water as well as the concentration of salt water)

Dependent Variable: Height

Control: the type of plant (sunflower) Hope this helps you! Ask me anything if you have any quistions!

8 0

3 years ago

Convert 22.4kg/l to kg/ml

Lady_Fox [76]

to be in kg/mL. What you need to do first is write 22.4 kg/L over 1. Divide this by 1000 because there are 1000 mL per L. Your equation will look like 22.4 kg/L over 1 divided by 1000/1. You end up getting .0224 kg/mL.

3 0

3 years ago

When methane ( CH4 ) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reac

slega [8]

<h2>Answer:</h2> $1.33*10^{-2}grams$

<h2>Explanations</h2>

The complete balanced equation for the given reaction is expressed as;

$CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$

Given the following parameters

Mass of CH4 = 5.90×10^−3 g = 0.0059grams

Determine the moles of methane

$\begin{gathered} moles\text{ of CH}_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CH}_4=\frac{0.0059}{16.04} \\ moles\text{ of CH}_4=0.000368moles \end{gathered}$

According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:

$\begin{gathered} moles\text{ of H}_2O=\frac{2}{1}\times0.000368 \\ moles\text{ of H}_2O=0.000736moles \end{gathered}$

Determine the mass of water produced

$\begin{gathered} Mass\text{ of H}_2O=moles\times molar\text{ mass} \\ Mass\text{ of H}_2O=0.000736\times18.02 \\ Mass\text{ of H}_2O=0.0133grams=1.33\times10^{-2}grams \end{gathered}$

Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams

5 0

1 year ago

Carbon dioxide in the atmosphere can be reduced by _.*​

Carbon dioxide in the atmosphere can be reduced by _.*