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3 years ago

Carbon dioxide in the atmosphere can be reduced by _.*

Chemistry

2 answers:

Dima020 [189]3 years ago

7 0

Answer:

Less driving by yourself and more carpooling to reduce the amount of cars releasing Carbon dioxide into the air.

Explanation:

pychu [463]3 years ago

6 0

Answer:

As the use of plants as carbon sinks can be undone by events such as wildfires, the long-term reliability of these approaches has been questioned. Carbon dioxide that has been removed from the atmosphere can also be stored in the Earth's crust by injecting it into the subsurface, or in the form of insoluble carbonate salts (mineral sequestration).

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Explanation:

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zheka24 [161]

Answer:

Mass = 8 g

Explanation:

Given data:

Mass of MgO formed = 20 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

2Mg + O₂ → 2MgO

Number of moles of MgO:

Number of moles = mass/molar mass

Number of moles = 20 g/ 40 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of MgO and O₂ from balance chemical equation:

MgO : O₂

2 : 1

0.5 : 1/2×0.5 = 0.25 mol

Mass of oxygen required:

Mass = number of moles × molar mass

Molar mass of O₂ is 32 g/mol

Mass = 0.25 mol × 32 g/mol

Mass = 8 g

4 0

3 years ago

Compare the two types of optical telescopes

Jet001 [13]

Answer: Reflectors use a mirror to collect the light, whilst refractors use a lens while, Refractor telescopes require a large lens at the front to direct the incoming light to the lens.

3 0

3 years ago

2. Suppose 13.7 g of C2H2 reacts with 18.5 g O2 according to the reaction below. C2H2(g) + O2(g) → CO2(g) + H2O(ℓ) a. What is th

max2010maxim [7]

Answer:

Mass of CO₂ produced = 20.328 g

Oxygen is limiting reagent.

Explanation:

Given data:

Mass of C₂H₂ = 13.7 g

Mass of O₂ = 18.5 g

Mass of CO₂ produced = ?

What is limiting reagent = ?

Solution:

Chemical equation:

2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

Number of moles of C₂H₂:

Number of moles = mass /molar mass

Number of moles = 13.7 g/ 26.04 g/mol

Number of moles = 0.526 mol

Number of moles of O₂:

Number of moles = mass /molar mass

Number of moles = 18.5 g/ 32 g/mol

Number of moles = 0.578 mol

Now we will compare the moles of CO₂ with C₂H₂ and O₂

C₂H₂ : CO₂

2 : 4

0.526 : 4/2×0.526 = 1.052

O₂ : CO₂

5 : 4

0.578 : 4/5×0.578 = 0.462

The number of moles of CO₂ produced by O₂ are less thus oxygen will be limiting reactant.

Mass of CO₂ produced:

Mass = number of moles × molar mass

Mass = 0.462 mol × 44 g/mol

Mass = 20.328 g

7 0

3 years ago

The following data was collected when a reaction was performed experimentally in the laboratory.

Lera25 [3.4K]

Answer:

Mass = 279.23 g

Explanation:

Given data:

Number of moles of Fe₂O₃ = 3 mol

Number of moles of Al = 5 mol

Maximum amount of iron produced by reaction = ?

Solution:

Chemical equation:

Fe₂O₃ + 2Al → Al₂O₃ + 2Fe

Now we will compare the moles of iron with Al and iron oxide.

Fe₂O₃ : Fe

1 : 2

3 : 2×3 = 6 mol

Al : Fe

2 : 2

5 : 5 mol

The number of moles of iron produced by Al are less so Al is limiting reacting and it will limit the amount of iron so maximum number of iron produced are 5 moles.

Mass of iron:

Mass = number of moles × molar mass

Mass = 5 mol × 55.845 g/mol

Mass = 279.23 g

3 0

3 years ago

Nio conducts a science experiment. He puts yeast into a bottle with water and sugar, and then caps the bottle with a balloon. He

skad [1K]

Answer:the answer is a chemical change, because a gas was produced

Explanation: yeast is a chemical

4 0

4 years ago

Carbon dioxide in the atmosphere can be reduced by _.*​

Carbon dioxide in the atmosphere can be reduced by _.*