Which best describes the forces identified by Newton’s third law of motion?

Physics

2 answers:

Natali5045456 [20]4 years ago

5 0

Best answer is A: Equal and acting on different objects

Explanation, according to the third law of motion, this is how it works.

I can also confirm that I have tested on this question and got 100% on that test, so this answer has to be correct.

egoroff_w [7]4 years ago

4 0

equal and acting on different objects

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A firecracker is thrown downward from a height of 2.75m above the ground, with a speed of 3.15m/s. Ignore air resistance, determ

3241004551 [841]

Here in this question as we can see there is no air friction so we can use the principle of energy conservation

$PE_i + KE_i = PE_f + KE_f$

$mgh_1 + \frac{1}{2}mv_i^2 = mgh_2 + \frac{1}{2}mv_f^2$

now here we know that

$h_1 = 2.75 m$

$v_i = 0$

$v_f = 5.23 m/s$

now plug in all values in above equation

$mg*2.75 + 0 = mgh + \frac{1}{2}m(5.23)^2$

divide whole equation by mass "m"

$9.8*2.75 = 9.8*h + \frac{1}{2}*27.35$

$9.8*h = 13.27$

$h = 1.35 m$

so height of the ball from ground will be 1.35 m

4 0

3 years ago

The less mass an object has, the --- its gravitational f

BaLLatris [955]

Answer:

The less mass an object has, the less its gravitational [force.]

Explanation:

Newton's Law of Gravity states that $F_G=\frac{Gm_1m_2}{r^{2}}$ . The two m values are the objects' masses, G is the gravitational constant, and r is the distance between the objects' centers. Notice how the mass values are in the fraction's numerator? That means increasing the mass of one or both objects increases $F_G$ . That also implies the inverse; decreasing the mass of one or both objects decreases $F_G$ !