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3 years ago

Which best describes the forces identified by Newton’s third law of motion?

Physics

2 answers:

Natali5045456 [20]3 years ago

5 0

Best answer is A: Equal and acting on different objects

Explanation, according to the third law of motion, this is how it works.

I can also confirm that I have tested on this question and got 100% on that test, so this answer has to be correct.

egoroff_w [7]3 years ago

4 0

equal and acting on different objects

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An unbalanced force gives a 2.00 kg mass an acceleration of 5.00 m/s? What is the force applied to the object?

valentinak56 [21]

Answer:

10N

Explanation:

Equation: ΣF = ma

Fapp = ma

Fapp = (2kg)(5m/s^2) (im guessing you mean 5.00 m/s^2 not m/s)

Fapp = 10*kg*m/s^2

Fapp = 10N

5 0

2 years ago

Which statement accurately describes something that Yolanda can do as a part of her study?

Vikki [24]

Thank you for posting your question here at brainly. Below is Yoland's study:

Yolanda is studying two waves. The first wave has an amplitude of 2 m, and the second has an amplitude of 3 m.

I think the answer is "She can use constructive interference to generate a wave with an amplitude of 1.5 m."

6 0

3 years ago

Read 2 more answers

A skater with a mass of 72 kg is traveling east at 5.8 m/s when he collides with another skater of mass 45 kg heading 60° south

Akimi4 [234]

The final velocity is 5.87 m/s

Explanation:

Given-

mass, $m_{1}$ = 72 kg

speed, $v_{1}$ = 5.8 m/s

$Mass_{2}$ , $m_{2}$ = 45 kg

$speed_{2}$ , $v_{2}$ = 12 m/s

Θ = 60°

Final velocity, v = ?

Applying the conservation of momentum:

$m_{1}$ X $v_{1}$ + $m_{2}$ X $v_{2}$ = ( $m_{1}$ + $m_{2}$ ) v

72 X 5.8 + 45 X 12 X cos 60° = (72 + 45) v

v = 417.6 + 540 X $\frac{0.5}{117}$

v = 417.6 + $\frac{270}{117}$

v = 5.87 m/s

The final velocity is 5.87 m/s

8 0

3 years ago

Chromosomes that carry the same set of genes is called a ________ Chromosome.

Leokris [45]

It is called a homologous chromosome meaning it carries the same gene

3 0

3 years ago

A proposed communication satellite would revolve around the earth in a circular orbit in the equatorial plane at a height of 358

aleksandr82 [10.1K]

Answer:

Period is 86811.5 seconds.

Explanation:

${ \boxed{ \bf{T {}^{2} = (\frac{4 {\pi}^{2} }{GM}) {r}^{3} }}}$

${ \tt{T {}^{2} = \frac{4 {(3.14)}^{2} }{(6.6 \times {10}^{ - 11} ) \times (5.98 \times {10}^{24} )} \times {((35880\times {10}^{3}) } + (6370 \times {10}^{3} )) {}^{3} }} \\ \\ { \tt{T {}^{2} = 7.54 \times {10}^{9} }} \\ { \tt{T = \sqrt{7.54 \times {10}^{9} } }} \\ { \tt{T = 86811.5 \: seconds}}$

6 0

3 years ago