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bagirrra123 [75]
4 years ago
8

5. Would the bruises on the dead man have formed in the epithelia

Physics
1 answer:
ozzi4 years ago
8 0

The Answer is: underlying connective tissue

Explanation: bruise is said to be blood or bleeding under the skin as a result of trauma. Bruises form under the skin while epithelial tissues are on the body surface and as such the bruise on the dead man is in the underlying connective tissue.

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50°C is equivalent to a 82 F b- 90"F c 122"F
andre [41]

Answer:

50°C = 122 Fahrenheit

Explanation:

Here, we need to convert 50°C to F i.e. Fahrenheit. The conversion formula from degree Celsius to Fahrenheit is as follows :

^{\circ}F=(^{\circ}C\times \dfrac{9}{5})+32

Where, ^{\circ}C=50^{\circ}C

^{\circ}F=(50\times \dfrac{9}{5})+32

^{\circ}F=122^{\circ} F

So, 50 degree Celsius is equal to 122 degree Fahrenheit. Hence, this is the required solution.

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Read 2 more answers
A solid wood door 1.00 m wide and 2.00 m high is hinged along one side and has a total mass of 40.0 kg. Initially open and at re
xxTIMURxx [149]

Answer:

The final angular speed is 0.223 rad/s

Explanation:

By the conservation of angular moment:

ΔL=0

L₁=L₂

L₁ is the initial angular moment

L₂ is the final angular moment

L₁ is given by:

L_1=L_{door} + L_{mud}

As the door is at rest its angular moment is zero and the angular moment of mud can be considered as a point object, then:

L_1= L_{mud}= mvr

where

r is the distance from the support point to the axis of rotation (the mud hits at the center of the door; r=0.5 m)

v is the speed

m is the mass of the mud

L₂ is given by:

L_2= (I_{door} + I_{mud}) \omega_f

ωf is the final angular speed

The moment of inertia of the door can be considered as a rectangular plate:

I_{door}=\frac{1}{3}MW^2

M is the mass of the door

W is the width of the door

The moment of inertia of the mud is:

I_{mud}=mr^2

Hence,

L_1=L_2\\mvr= (I_{door} + I_{mud}) \omega_f\\\omega_f=\frac{mvr}{I_{door} + I_{mud}} \\\omega_f=\frac{mvr}{I_{door} + I_{mud}}

\omega_f=\frac{0.5kg \times 12m/s \times 0.5m}{\frac{1}{3}40kg(1m)^2+0.5kg \times (0.5m)^2}

\omega_f=0.223 \frac{rad}{s}

6 0
4 years ago
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