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3 years ago

How to contact brainly

Physics

2 answers:

LekaFEV [45]3 years ago

7 0

Answer:

go and rate brainly you can get question them

nevsk [136]3 years ago

5 0

Answer:

Go to your play store and rate their app

If you have any problem u can even mention that while you are rating them

I am sorry if I said anything wrong

You might be interested in

All BUT one statement applies to electromagnetic radiation. That is

koban [17]

A) Radio waves are a form of electromagnetic radiation.

TRUE

It is the type of electromagnetic wave with least energy range and longest wavelength range among all

B) Electromagnetic radiation does not require a medium to travel.

TRUE

This radiation can travel through vacuum also and its speed is maximum in vacuum

C) In a vacuum, electromagnetic radiation travels at the speed of light.

TRUE

speed of all electromagnetic radiation is same as speed of light in vacuum

D) Electromagnetic radiation travels in the form of longitudinal waves.

FALSE

All electromagnetic radiation is always in form of transverse waves

So correct options are

4 0

3 years ago

The 68-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P

bogdanovich [222]

Explanation:

Mass of the crate, m = 68 kg

We need to find the resulting acceleration if :

(a) Force, P = 0

P = m a

⇒ a = 0

(b) P = 181 N

$a=\dfrac{P}{m}$

$a=\dfrac{181\ N}{68\ kg}$

$a=2.67\ m/s^2$

(c) P = 352 N

$a=\dfrac{P}{m}$

$a=\dfrac{352\ N}{68\ kg}$

$a=5.17\ m/s^2$

Hence, this is the required solution.

5 0

3 years ago

a ladybug sits at the outer edge of a merry-go-round and a gentleman bug sits halfway between her and the axis of rotation. The

forsale [732]

The gentleman bug's angular speed is the same as the ladybug's (1 rev/s)

6 0

3 years ago

Find the total electric charge of 1.7 kg of electrons. me=9.11×10−31kg, e=1.60×10−19C.

Gelneren [198K]

Answer:

$2.99\cdot 10^{11}C$

Explanation:

The mass of one electron is

$m_e = 9.11\cdot 10^{-31}kg$

So the number of electrons contained in M=1.7 kg of mass is

$N=\frac{M}{m_e}=\frac{1.7 kg}{9.11\cdot 10^{-31}kg}=1.87\cdot 10^{30}$

The charge of one electron is

$e=1.60\cdot 10^{-19} C$

So, the total charge of these electrons is equal to the charge of one electron times the number of electrons:

$Q=Ne=(1.87\cdot 10^{30})(1.6\cdot 10^{-19}C)=2.99\cdot 10^{11}C$

8 0

3 years ago

calculate the efficiency of a light bulb that had an input of 400 j transfers 100j as a light and 300j as heat.

beks73 [17]

Efficiency = useful energy out / total energy in x 100
= 100/400 x 100
=0.25 x 100
= 25%

25%

6 0

2 years ago