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tamaranim1 [39]
3 years ago
5

What happens to the gravitational force between two objects when the distance between them increases by 3 times?

Physics
1 answer:
quester [9]3 years ago
3 0

Answer:

it decrease by 9 times

Explanation:

If the separation distance between any two objects is tripled (increased by a factor of 3), then the force of gravitational attraction is decreased by a factor of 9 (3 raised to the second power).

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Answer:

THES IS NOT

Explanation:

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7 0
3 years ago
The force required to open air bags is dangerous for:
pentagon [3]

It is dangerous for children. Air bags are dangerous to children age 12 and under because the bag inflates at speeds up to 200 mph and that sudden blast of energy can severely injure or kill passengers who are too close to the air bag. If possible, children should ride in the center of back seat, properly restrained with a seat belt.

5 0
3 years ago
The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center. If
zvonat [6]

Answer:

The distance between their eye and the ceiling is 33.06 m.

Explanation:

Given that,

The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center, D = 4.35 mm

Diameter of the eye of pupil, d = 5.1 mm

Wavelength, \lambda=550\ nm

We need to find the distance between their eye and the ceiling. Using Rayleigh criteria, we get the distance as follows :

L=\dfrac{Dd}{1.22\lambda}\\\\L=\dfrac{4.35\times 10^{-3}\times 5.1\times 10^{-3}}{1.22\times 550\times 10^{-9}}\\\\L=33.06\ m

So, the distance between their eye and the ceiling is 33.06 m.

3 0
3 years ago
Which are not in the nucleus? Check all that apply
Ivenika [448]
Ions and electrons -apex!
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4 years ago
Read 2 more answers
Find the wavelength of a photon which has 500.0 eV of energy.
jekas [21]

Answer:

2.5 x 10⁻⁹ m

Explanation:

E = Energy of photon = 500 eV = 500 x 1.6 x 10⁻¹⁹ J

c = speed of photon = 3 x 10⁸ m/s

λ = wavelength of photon = ?

Energy of photon is given as

E = \frac{hc}{\lambda }

inserting the values

500\times 1.6\times 10^{-19} = \frac{(6.63\times 10^{-34})(3\times 10^{8})}{\lambda }

λ = 2.5 x 10⁻⁹ m

5 0
4 years ago
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