All categories

2 years ago

What happens to the gravitational force between two objects when the distance between them increases by 3 times?

Physics

1 answer:

quester [9]2 years ago

3 0

Answer:

it decrease by 9 times

Explanation:

If the separation distance between any two objects is tripled (increased by a factor of 3), then the force of gravitational attraction is decreased by a factor of 9 (3 raised to the second power).

You might be interested in

I Need answer ASAP

anzhelika [568]

Answer: Convection and conduction

Tell me that I got it right??

Explanation

Mark me as Brainliest PLEASE I HAVE 0 BRAINLIEST

3 0

3 years ago

Read 2 more answers

4.A 31-cm long conducting wire of 9-g carrying 7- A current is placed in a uniform magnetic field. What are the strength and dir

Anika [276]

Answer

Given,

Length of the wire,L = 31 cm = 0.31 m

mass of the wire, m = 9 g = 0.009 Kg

Current in the wire,I = 7 A

Magnetic field strength, B= ?

Equating magnetic force to the weight of the wire.

$BIL = m g$

$B=\dfrac{m g}{IL}$

$B=\dfrac{0.009\times 9.81}{7\times 0.31}$

B = 0.0407 T

For Force to be upward magnetic field direction should be outward of the plane of paper.

7 0

3 years ago

Indicate whether the statement is true or false. A hypothesis is not scientific if there exists no test for proving it wrong.

elena-s [515]

A. TRUE
A hypothesis must be based on scientific principles and rules in order to be experimented

5 0

3 years ago

A 2.00 meter long horizontal plank whose mass is 3.00 kg is placed so that the very end (the right end) rests on a retaining wal

avanturin [10]

Answer:

$R_g=\frac{61}{7} =8.7143\ N$

$R_w=45.1857\ N$

Explanation:

Given that:

mass of plank, $m=3\ kg$

length of plank, $l=2\ m$

From the image we can visualize the given situation.

Consider the given plank to be mass-less and having a uniformly distributed mass of 1.5 kg per meter.

<u>Now in the balanced condition:</u>

$\sum F=0$

$R_g+R_w=(3+2.5)\times 9.8$

$R_g+R_w=53.9\ N$ .......................(1)

$\sum M_w=0$

$1.75\times R_g=3\times 1+(2.5\times 9.8)\times 0.5$

$R_g=\frac{61}{7} =8.7143\ N$ ...........................(2)

is the force acted by the tailgate on the plank.

<u>Substitute the value from (2) into (1):</u>

$R_w=45.1857\ N$ is the force acted by the wall upon the plank.

6 0

3 years ago

A van traveling down a slope with a uniform acceleration of 2.15 meters/second2 attains a speed of 20.00 meters/second after 7.0

jeka94

-- While gaining 2.15 m/s more speed every second, the van
would gain (2.15 x 7) = 15.05 m/s more speed in 7 seconds.

-- We're told that its speed at the end of the 7 seconds
is 20 m/s .

-- So its speed at the beginning of the 7 seconds must have been

(20 m/s - 15.05 m/s) = 4.95 m/s .

8 0

2 years ago

Read 2 more answers