If john takes 45 minutes to bicycle a total of four kilometers to his grandmother’s house, what is his velocity in km/hr

Visible light travels at a speed 3.0 × 108 of m/s. If red light has a wavelength of 6.5 × 10–7 m, what the frequency of this lig

gayaneshka [121]

i think its d on edge

4 0

3 years ago

Read 2 more answers

What is the pressure if a force of 200 N is applied over an area of

Gelneren [198K]

The pressure is $4 N / c m^{2}$ .

Answer: Option A

<u>Explanation:</u>

Pressure defines the force acting per single area. So depending upon the amount of force acting over a given area in the perpendicular direction of the object, the pressure acting on that area will vary.

So the pressure is directly proportionate to the applied force on a particular region and inversely proportionate into the areas of the region. Hence, the unit of pressure is considered as $N / c m^{2}$ or Pascal. Pressure can also be termed as the number of air molecules present in a specified closed region. Thus, for the present condition

$\text { Pressure }=\frac{\text { Force }}{\text { Area }}$

Thus, by appling the given values in the above equation, we get,

$\text { Pressure }=\frac{200}{50}$ = $4 N / c m^{2}$

So the pressure is $4 N / c m^{2}$ .

6 0

3 years ago

Presuming you have a closed circuit, when you thrust a bar magnet to and fro into a coil of wire, you induce:________.

Art [367]

Hedndjf Hinduism’s jeirbduddn dudurnidkd idbehdududid idjdjdudud idjdbdudud idisjdbdbd

7 0

3 years ago

Question 3 A woman sitting in a stationary car notices a man cycling past her at 40 km/hr. Five seconds after he passes her car,

Naya [18.7K]

The shortest possible distance in which she catches up with the man is 129.7 m.

The given parameters:

speed of the man, v₁ = 40 km/hr

speed of the woman, v₂ = 70 km/hr

time when the woman started moving, t₁ = 5 seconds

To find:

the shortest distance when she catches up with the man

Convert the given speed in km/h to m/s

3.6 km/h = 1 m/s
40 km/h = 40/3.6 = 11.11 m/s
70 km/h = 70/3.6 = 19.44 m/s

Calculate the distance moved by the man before she started following him.

Distance moved by the man = speed x time

= 11.11 m/s x 5 s

= 55.55 m

Let the time the woman catches up with the man = t

Apply the following simple principle to calculate the time.

The man is moving forward and the woman is moving forward to close the gap between them, thus both speeds are working against each other.

$(v_2-v_1)t = 55.55 \ m$

the difference in the speed is because they are working against each other.

$(19.44 - 11.11)t = 55.55\\\\8.33t = 55.55\\\\t = \frac{55.55}{8.33} \\\\t = 6.67 \ s$

The time when the woman catches up with the man = 6.67 s

The shortest distance at which the woman catches up with the man is calculated as;

Shortest distance = woman's speed x time when she catches up

= 19.44 m/s x 6.67 s

= 129.7 m

Thus, the shortest possible distance in which she catches up with the man is 129.7 m.

Learn more here: https://brainly.in/question/9541933?tbs_match=3

5 0

3 years ago

A particle moving in simple harmonic motion with a period T = 1.5 s passes through the equilibrium point at time t0 = 0 with a v

ch4aika [34]

Answer

given,

Time period= T = 1.5 s

If it's moving through equilibrium point at t₀= 0 with v = 1.0 m/s

v_max=1.00 m/s

we know,

v_ max=A ω

v = A sin (ωt)

-0.50= -1.00 sin (ωt)

sin (ωt) = 0.5

$\omega t = sin^{-1}(0.5)$

$\dfrac{2\pi}{T}\times t =0.524$

$\dfrac{2\pi}{1.5}\times t =0.524$

t = 0.125 s

we have time period T=1.5 it is the time to complete one oscillation

means from eq to right,then left,then eq,then left,then from right to eq

time taken for left = t/4 = 0.125/4 = 0.375 s

smallest value of time

=0.375 + 0.125

= 0.50 sec

7 0

3 years ago