Answer:
the velocity of car when it passes the truck is u = 16.33 m/s
Explanation:
given,
constant speed of truck = 28 m/s
acceleration of car = 1.2 m/s²
passes the truck in 545 m
speed of the car when it just pass the truck = ?
time taken by the truck to travel 545 m
time =
time =
time =19.46 s
velocity of the car when it crosses the truck
![S = ut + \dfrac{1}{2}at^2](https://tex.z-dn.net/?f=S%20%3D%20ut%20%2B%20%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
![545= u\times 19.46 + \dfrac{1}{2} \times 1.2 \times 19.46^2](https://tex.z-dn.net/?f=545%3D%20u%5Ctimes%2019.46%20%2B%20%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%201.2%20%5Ctimes%2019.46%5E2)
u = 16.33 m/s
the velocity of car when it passes the truck is u = 16.33 m/s
You can use fixture wires: For installation in luminaires where they are enclosed and protected and not subject to bending and twisting and also can be used to connect luminaires to their branch circuit conductors.
<h3>What are some uses of fixture wires?</h3>
Fixture wires are flexible conductors that are used for wiring fixtures and control circuits. There are some special uses and requirements for fixture wires and no fixture can be smaller than 18 AWG
In modern fixtures, neutral wire is white and the hot wire is red or black. In some types of fixtures, both wires will be of the same color.
To know more about fixture wires, refer
brainly.com/question/26098282
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Answer:
EXplained
Explanation:
from conservation of energy
change in potential energy = gain in kinetic energy
so as all he balls are throws from the same height thus the change in potential energy is the same for all the balls thus the gain in kinetic energy is the same for all the balls and as they have the same initial velocity thus the final velocity is the same for all the balls.
Answer:
mass of the object is 2.18 kg
Explanation:
Given
Force (F) = 8.5 N = 8.5 kg.m/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
acceleration (a) = 3.9 m/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
Mass (m) = ?
We know that the newton's second law of motion gives the relation between mass of ab object. force acted upon and the amount the object is accelerated. It is expressed in the form of an equation:
F = ma
mass, m = F/a
= ![\frac{8.5 kgms^{-2} }{3.9 ms^{-2} }](https://tex.z-dn.net/?f=%5Cfrac%7B8.5%20kgms%5E%7B-2%7D%20%7D%7B3.9%20ms%5E%7B-2%7D%20%7D)
= 2.18 kg