9. $12,50
10. $17.50 (ripoff lol)
11. Clearly Alastair, they got some strong muscles
12. Taryn would be charging $15 an hour and alastair $24.50 an hour. $735 divided by $15 an hour equals 49 hours for Taryn. $735 divided by $24.50 an hour equals 30 hours for Alastair.
13a. 5 minutes to make a sculpture and 7 balloons in a sculpture
13b. Tomas uses 1.4 balloons a minute
13c. 14 balloons (tip. when multiplying a decimal by 10, 100, etc, just move the decimal for the number of zeroes.) 1.4x10 = 14. Simply move the decimal to the right one because there is one zero in 10.
13c blanks. The first blank is 1.4 and the second blank is 14
14. 8 pound bag of dog food is a way better deal!
15. $10.50
16a. The price for 25 whistles is $0.85 each, 50 whistles for $0.72 each, or 80 whistles for $0.75 each. The difference between the highest number and lowest number is $0.13 or 13 cents.
16b. $0.34 or 34 cents
16c. She should order 80 Kazoos <em>not a meme reference</em>
I hope all of this helped! It took forever!
Answer with explanation:
Given the function f from R to 
f: 

To prove that the function is objective from R to 
Proof:

When we prove the function is bijective then we proves that function is one-one and onto.
First we prove that function is one-one
Let 

Cancel power on both side then we get

Hence, the function is one-one on domain [tex[(0,\infty)[/tex].
Now , we prove that function is onto function.
Let - f(x)=y
Then we get 

The value of y is taken from 
Therefore, we can find pre image for every value of y.
Hence, the function is onto function on domain 
Therefore, the given
is bijective function on
not on whole domain R .
Hence, proved.
The answer is $37,923
<span>y = 844.697x^2 + 3723.485x - 13,650
x - number of years
y - the annual profit
If x = 8, the annual profit y is:
y = </span>844.697 * 8^2 + 3723.485 * 8 - 13,650
y = 844.697 * 64 + 29,787.88 - 13,650
y = 54,060.608 + 16,137.88
y = 37,922.728 ≈ 37,923
U + 4/5 = 2 and 1/3
Subtract 4/5 from each side of the equation:
U = (2 and 1/3) - (4/5)
Now it's just problem in plain old adding and subtracting fractions,
just like the ones you've done many times before.
First let's change (2 and 1/3) to a fraction: 2 and 1/3 = 7/3
So you have to find the value of (7/3) - (4/5) .
In order to add or subtract fractions, they need to have a common denominator.
The least common multiple of 3 and 5 is 15, so that's a good choice.
7/3 = 35/15
4/5 = 12/15
Now the problem is: (35/15) - (12/15).
That's 23/15 . . . . . the same thing as <u>1 and 8/15</u> .
That's the value of ' U '. What an ugly number !