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nata0808 [166]
3 years ago
10

Solve this problem 6.3=0.9y

Mathematics
2 answers:
Anni [7]3 years ago
7 0
6.3 = 0.9y 


y would equal 7
pochemuha3 years ago
6 0
Divide both side by 0.9 this will isolate the y 
y=6.3/0.9
y=7 
6.3=0.9(7)
6.3=6.3 check


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Pls answer 9-16 show work will give brainliest
iren [92.7K]

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12. Taryn would be charging $15 an hour and alastair $24.50 an hour. $735 divided by $15 an hour equals 49 hours for Taryn. $735 divided by $24.50 an hour equals 30 hours for Alastair.

13a. 5 minutes to make a sculpture and 7 balloons in a sculpture

13b. Tomas uses 1.4 balloons a minute

13c. 14 balloons (tip. when multiplying a decimal by 10, 100, etc, just move the decimal for the number of zeroes.) 1.4x10 = 14. Simply move the decimal to the right one because there is one zero in 10.

13c blanks. The first blank is 1.4 and the second blank is 14

14. 8 pound bag of dog food is a way better deal!

15. $10.50

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8 0
3 years ago
15 pts. Prove that the function f from R to (0, oo) is bijective if - f(x)=x2 if r- Hint: each piece of the function helps to "c
solniwko [45]

Answer with explanation:

Given the function f from R  to (0,\infty)

f: R\rightarrow(0,\infty)

-f(x)=x^2

To prove that  the function is objective from R to  (0,\infty)

Proof:

f:(0,\infty )\rightarrow(0,\infty)

When we prove the function is bijective then we proves that function is one-one and onto.

First we prove that function is one-one

Let f(x_1)=f(x_2)

(x_1)^2=(x_2)^2

Cancel power on both side then we get

x_1=x_2

Hence, the function is one-one on domain [tex[(0,\infty)[/tex].

Now , we prove that function is onto function.

Let - f(x)=y

Then we get y=x^2

x=\sqrt y

The value of y is taken from (0,\infty)

Therefore, we can find pre image  for every value of y.

Hence, the function is onto function on domain (0,\infty)

Therefore, the given f:R\rightarrow(0.\infty) is bijective function on (0,\infty) not on  whole domain  R .

Hence, proved.

3 0
3 years ago
What is the area of this figure?
sergiy2304 [10]

1.5 \times 3 = 4.5 \:  {(km)}^{2}

3 0
3 years ago
The equation y ̂=844.697x^2+3723.485x-13,650 models the annual profits of a new business, where x is the number of years since t
julsineya [31]
The answer is $37,923

<span>y = 844.697x^2 + 3723.485x - 13,650
x - number of years
y - the annual profit

If x = 8, the annual profit y is:
y = </span>844.697 * 8^2 + 3723.485 * 8 - 13,650
y = 844.697 * 64 + 29,787.88 - 13,650
y = 54,060.608 + 16,137.88
y = 37,922.728 ≈ 37,923
5 0
4 years ago
Help me solve for U please help
Maurinko [17]
U + 4/5 = 2 and 1/3

Subtract 4/5 from each side of the equation:

U = (2 and 1/3) - (4/5)

Now it's just problem in plain old adding and subtracting fractions,
just like the ones you've done many times before.

First let's change (2 and 1/3) to a fraction:    2 and 1/3  =  7/3

So you have to find the value of  (7/3) - (4/5) .

In order to add or subtract fractions, they need to have a common denominator.
The least common multiple of 3 and 5 is 15, so that's a good choice.

7/3 = 35/15
4/5 = 12/15

Now the problem is:     (35/15) - (12/15).  

That's 23/15 . . . . . the same thing as <u>1 and 8/15</u> .  

That's the value of ' U '.  What an ugly number !
8 0
3 years ago
Read 2 more answers
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